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Javascript 替换链接href中的src img var wrap=$('').appendTo(li); var img=$('').appendTo(wrap);_Javascript_Jquery - Fatal编程技术网

Javascript 替换链接href中的src img var wrap=$('').appendTo(li); var img=$('').appendTo(wrap);

Javascript 替换链接href中的src img var wrap=$('').appendTo(li); var img=$('').appendTo(wrap);,javascript,jquery,Javascript,Jquery,在这里写什么href=“”在字符串var wrap=$('').appendTo(li)?我想您应该这样做: var wrap = $('<a class="fancybox" href=""></a>').appendTo(li); var img = $('<img/>').appendTo(wrap); var wrap=$('').appendTo(li); var img=$('').appendTo(wrap); $(wrap.attr('hr

在这里写什么href=“”在字符串
var wrap=$('').appendTo(li)

我想您应该这样做:

var wrap = $('<a class="fancybox" href=""></a>').appendTo(li);

var img = $('<img/>').appendTo(wrap);
var wrap=$('').appendTo(li);
var img=$('').appendTo(wrap);
$(wrap.attr('href',$(img.attr('src'));

我不太明白你的意思,但这是你想要的吗

   var wrap = $('<a class="fancybox" href=""></a>').appendTo(li);

   var img = $('<img src="YOUR_IMAGE_URL" />').appendTo(wrap);

    $(wrap).attr('href', $(img).attr('src'));
var wrap=$('').appendTo(li);

var img=$('您必须像
href=“www.mylink.com”
那样编写链接的路径,我需要img的src点作为链接的href。但是您还没有设置
src
属性!我需要这样的东西,但它不起作用。
var wrap=$('').appendTo(li);var img=$('
var wrap = $('<a class="fancybox" href="myimage.jpg"></a>').appendTo(li);
var img = $('<img/>').appendTo(wrap);
img.attr('src',wrap.attr('href'));