Javascript 按首字母顺序对JSON排序
我有这样一个JSON:Javascript 按首字母顺序对JSON排序,javascript,laravel-5,vuejs2,Javascript,Laravel 5,Vuejs2,我有这样一个JSON: [ { "id": 1, "slug": "abakan", "name": "Абакан" }, { "id": 4, "slug": "almetevsk", "name": "Альметьевск" }, { "id": 10, "slug": "astrahan", "name": "Астрахань" }, { "id": 11, "slug
[
{
"id": 1,
"slug": "abakan",
"name": "Абакан"
},
{
"id": 4,
"slug": "almetevsk",
"name": "Альметьевск"
},
{
"id": 10,
"slug": "astrahan",
"name": "Астрахань"
},
{
"id": 11,
"slug": "barnaul",
"name": "Барнаул"
},
...
]
通过这种方法得到:
public function getCities()
{
$cities = City::mainCities()->get(['id', 'slug', 'name']);
return response()->json($cities);
}
我如何按字母顺序和字母顺序对列表进行排序。例如:
"A": [
{
"id": 1,
"slug": "abakan",
"name": "Абакан"
},
{
"id": 4,
"slug": "almetevsk",
"name": "Альметьевск"
}
],
"B": [
{
"id": 11,
"slug": "barnaul",
"name": "Барнаул"
},
...
]
等等
我的后端是Laravel,前端是VueJS。这对我很有用:
var items = [
{
"id": 11,
"slug": "barnaul",
"name": "Барнаул"
},
{
"id": 1,
"slug": "abakan",
"name": "Абакан"
},
{
"id": 4,
"slug": "almetevsk",
"name": "Альметьевск"
},
{
"id": 10,
"slug": "astrahan",
"name": "Астрахань"
}
];
var sortedItems = items.sort((a, b) => a.slug.localeCompare(b.slug));
var results = {};
for (var i = 0; i < 26; i++) {
var char = String.fromCharCode(97 + i);
var bigChar = char.toUpperCase();
results[bigChar] = [];
for (var s = 0; s < sortedItems.length; s++) {
if (sortedItems[s].slug.startsWith(char)) {
results[bigChar].push(sortedItems[s]);
}
}
}
console.log(results)
var项目=[
{
“id”:11,
“鼻涕虫”:“巴诺”,
“名称”:“Бааааааааа”
},
{
“id”:1,
“鼻涕虫”:“阿巴坎”,
“名称”:“Ааааааа”
},
{
“id”:4,
“slug”:“almetevsk”,
“名称”:“А峈峈峈峈峈峈峈峈峈峈2375
},
{
“id”:10,
“鼻涕虫”:“阿斯特拉罕”,
“名称”:“АСаааа”
}
];
var sortedItems=items.sort((a,b)=>a.slug.localeCompare(b.slug));
var结果={};
对于(变量i=0;i<26;i++){
var char=String.fromCharCode(97+i);
var bigChar=char.toUpperCase();
结果[bigChar]=[];
对于(var s=0;s
我的解决方案:
var城市=[
{id:1,slug:“abakan”,名字:“Аааааа”},
{id:4,slug:“almetevsk”,名字:“Ааааааааааааа1072,
{id:11,slug:“barnaul”,名字:“Бааааааа”},
{id:10,鼻涕虫:“阿斯特拉罕”,名字:“АСаааа”}
];
城市.排序(功能(a,b){
返回a.slug[0].localeCompare(b.slug[0]);
});
var newCities={};
对于(变量i=0;i=0)
新城市[c].push(城市[i]);
否则{
新城[c]=[];
新城市[c].push(城市[i]);
}
}
console.log(新城)代码>这个答案可能已经在这里得到了回答:希望这有帮助!