Javascript 如何修改对象数组中的json对象
我有一个对象数组Javascript 如何修改对象数组中的json对象,javascript,arrays,angularjs,json,asp.net-web-api,Javascript,Arrays,Angularjs,Json,Asp.net Web Api,我有一个对象数组 // This is should be taken from database $scope.users = [{"$id":"1","UserID":3,"Name":"A","Selected":false},{"$id":"2","UserID":4,"Name":"B","Selected":false},{"$id":"3","UserID":5,"Name":"C","Selected":false},{"$id":"4","UserID":6,"Name":"D
// This is should be taken from database
$scope.users = [{"$id":"1","UserID":3,"Name":"A","Selected":false},{"$id":"2","UserID":4,"Name":"B","Selected":false},{"$id":"3","UserID":5,"Name":"C","Selected":false},{"$id":"4","UserID":6,"Name":"D","Selected":false}]
然后是一个数组,其中包含上一屏幕中选定的用户
$scope.usersSelected = [{"$id":"3","UserID":5,"Name":"C","Selected":true,"$$hashKey":"object:83"},{"$id":"4","UserID":6,"Name":"D","Selected":true,"$$hashKey":"object:84"}]
我想更新$scope.users的所选属性,如果在$scope.usersSelected
中找到它们。因此,我迭代了$scope.users选中的UserID
,然后在$scope.users的UserID
中搜索它的UserID
for (var i = 0; i < $scope.usersSelected.length; i++) {
var obj = $.grep($scope.users, function (e) { return e.UserID == $scope.usersSelected[i].UserID; });
obj.Selected = true;
}
for(var i=0;i<$scope.usersseselected.length;i++){
var obj=$.grep($scope.users,函数(e){return e.UserID==$scope.usersSelected[i].UserID;});
所选对象=真;
}
但是所选的属性将不会更新。上面的代码有什么问题
其次,我需要一个关于上面数组中数据的解释,为什么从数据库填充数据时总是有“$id”
,从另一个屏幕获取数据时总是有“$$hashKey”
?这些价值观从何而来
注意:我正在使用AngularJS和ASP.NET Web API 2从数据库获取数据。使用javascript测试
usersSelected = $scope.usersSelected;
users = $scope.users;
for (var i=0;i<users.length;i++){
if (usersSelected.some(function(e) e.UserID == users[i].UserID)) {
users[i].Selected = true;
console.dir(users[i]);
}
}
usersSelected=$scope.usersSelected;
users=$scope.users;
对于使用javascript测试的(var i=0;i)
usersSelected = $scope.usersSelected;
users = $scope.users;
for (var i=0;i<users.length;i++){
if (usersSelected.some(function(e) e.UserID == users[i].UserID)) {
users[i].Selected = true;
console.dir(users[i]);
}
}
usersSelected=$scope.usersSelected;
users=$scope.users;
对于(var i=0;i测试,工作绝对正常
$scope.users = [ {
"$id" : "1",
"UserID" : 3,
"Name" : "A",
"Selected" : false
}, {
"$id" : "2",
"UserID" : 4,
"Name" : "B",
"Selected" : false
}, {
"$id" : "3",
"UserID" : 5,
"Name" : "C",
"Selected" : false
}, {
"$id" : "4",
"UserID" : 6,
"Name" : "D",
"Selected" : false
} ];
$scope.usersSelected = [ {
"$id" : "3",
"UserID" : 5,
"Name" : "C",
"Selected" : true,
"$$hashKey" : "object:83"
}, {
"$id" : "4",
"UserID" : 6,
"Name" : "D",
"Selected" : true,
"$$hashKey" : "object:84"
} ]
var users = $scope.users;
var usersSelected = $scope.usersSelected;
for (var i = 0; i < users.length; i++) {
for (var j = 0; j < usersSelected.length; j++) {
debugger
if (users[i].UserID == usersSelected[j].UserID) {
console.log(users[i].UserID)
console.log(usersSelected[j].UserID)
users[i].Selected = true;
}
}
}
console.log(users)
console.log(usersSelected);
$scope.users=[{
“$id”:“1”,
“用户ID”:3,
“姓名”:“A”,
“选定”:false
}, {
“$id”:“2”,
“用户ID”:4,
“名称”:“B”,
“选定”:false
}, {
“$id”:“3”,
“用户ID”:5,
“姓名”:“C”,
“选定”:false
}, {
“$id”:“4”,
“用户ID”:6,
“名称”:“D”,
“选定”:false
} ];
$scope.usersSelected=[{
“$id”:“3”,
“用户ID”:5,
“姓名”:“C”,
“选定”:正确,
“$$hashKey”:“对象:83”
}, {
“$id”:“4”,
“用户ID”:6,
“名称”:“D”,
“选定”:正确,
“$$hashKey”:“对象:84”
} ]
var users=$scope.users;
var usersSelected=$scope.usersSelected;
对于(var i=0;i
经过测试,工作完全正常
$scope.users = [ {
"$id" : "1",
"UserID" : 3,
"Name" : "A",
"Selected" : false
}, {
"$id" : "2",
"UserID" : 4,
"Name" : "B",
"Selected" : false
}, {
"$id" : "3",
"UserID" : 5,
"Name" : "C",
"Selected" : false
}, {
"$id" : "4",
"UserID" : 6,
"Name" : "D",
"Selected" : false
} ];
$scope.usersSelected = [ {
"$id" : "3",
"UserID" : 5,
"Name" : "C",
"Selected" : true,
"$$hashKey" : "object:83"
}, {
"$id" : "4",
"UserID" : 6,
"Name" : "D",
"Selected" : true,
"$$hashKey" : "object:84"
} ]
var users = $scope.users;
var usersSelected = $scope.usersSelected;
for (var i = 0; i < users.length; i++) {
for (var j = 0; j < usersSelected.length; j++) {
debugger
if (users[i].UserID == usersSelected[j].UserID) {
console.log(users[i].UserID)
console.log(usersSelected[j].UserID)
users[i].Selected = true;
}
}
}
console.log(users)
console.log(usersSelected);
$scope.users=[{
“$id”:“1”,
“用户ID”:3,
“姓名”:“A”,
“选定”:false
}, {
“$id”:“2”,
“用户ID”:4,
“名称”:“B”,
“选定”:false
}, {
“$id”:“3”,
“用户ID”:5,
“姓名”:“C”,
“选定”:false
}, {
“$id”:“4”,
“用户ID”:6,
“名称”:“D”,
“选定”:false
} ];
$scope.usersSelected=[{
“$id”:“3”,
“用户ID”:5,
“姓名”:“C”,
“选定”:正确,
“$$hashKey”:“对象:83”
}, {
“$id”:“4”,
“用户ID”:6,
“名称”:“D”,
“选定”:正确,
“$$hashKey”:“对象:84”
} ]
var users=$scope.users;
var usersSelected=$scope.usersSelected;
对于(var i=0;i
如果您想删除$hashkey
并像这样删除另一个angular.toJson()
它将删除man@SakthiSureshAnand,太好了,感谢您提供的信息,所以在angular中打印json时,应该使用angular.toJson()
而不是json.stringify()吗
?我建议你去下划线.js
如果你想删除$hashkey
,它有所有像Stuff一样迭代的方法,像这样做angular.toJson()
它会删除man@SakthiSureshAnand,太好了,感谢您提供的信息,所以在angular中打印json时,是否应该使用angular.toJson()
而不是JSON.stringify()
?我建议您使用underline.js
它有所有像Stuff一样迭代的方法,因为您使用的是angular,$不是jquery。您可以尝试将其转换为for Loop吗是的,但它仍然不起作用,下面是代码var users2=$scope.users;var usersSelected2=$scope.usersSelected;console.log('users2='+JSON.stringify(users2));$(users2).each(函数(i,d){if(usersSelected2.some(函数(e){e.UserID==d.UserID})){d.Selected=true;}});console.log('users2='+JSON.stringify(users2))
编辑了答案,你能运行那个精确的代码并查看一下吗。我已经调试过了,而且条件永远不会是真的,因为你使用的是angular,$不是jquery。你能试着将它转换为for Loop吗是的,但它仍然不起作用,下面是代码var users2=$scope.users;var usersSelected2=$scope.usersSelected;console.log('users2='+JSON.stringify(users2));$(users2).each(函数(i,d){if(usersSelected2.some(函数(e){e.UserID==d.UserID})){d.Selected=true;}});console.log('users2='+JSON.stringify(users2))
编辑了答案,你能运行那个精确的代码并查看一下吗。我已经调试过了,条件永远不会是真的。谢谢,它是有效的,但我们可以使用索引函数来获取对象吗?在使用$之前。grep
我使用了数组。索引函数()
但它不起作用。因为您正在迭代json whic的数组