Javascript 将返回的api数据设置为react状态
我正在尝试在下面设置此react组件的状态。变量rankAndTeam包含下面的prints=>数据。我希望华盛顿首都设置为此。state.teamRank[0]…纽约岛民设置为此。state.teamRank[1]等Javascript 将返回的api数据设置为react状态,javascript,node.js,reactjs,Javascript,Node.js,Reactjs,我正在尝试在下面设置此react组件的状态。变量rankAndTeam包含下面的prints=>数据。我希望华盛顿首都设置为此。state.teamRank[0]…纽约岛民设置为此。state.teamRank[1]等 this.state = { teamRank: { 0: "", 1: "", 2: "", 3: "", 4: "", 5: "", 6: ""
this.state = {
teamRank: {
0: "",
1: "",
2: "",
3: "",
4: "",
5: "",
6: "",
7: "",
}
}
}
async componentDidMount() {
const url2 = 'https://statsapi.web.nhl.com/api/v1/standings';
const response2 = await fetch(url2);
const data2 = await response2.json();
data2.records.map((element) => {
element.teamRecords.map((element2, index) => {
const teamNames = element2.team.name;
const rankAndTeam = teamNames + index;
console.log(rankAndTeam);
});
}
印刷品
Main.js:80Washington Capitals0
Main.js:80名纽约岛居民1
Main.js:80匹兹堡企鹅2
Main.js:80卡罗莱纳飓风3
Main.js:80哥伦布蓝色夹克4
Main.js:80费城传单5
Main.js:80纽约游骑兵6
Main.js:80新泽西魔鬼7
反应组分:
Want to put this.state.teamRank.['0'] where Name0 is...
Want to put this.state.teamRank.['1'] where Name1 is etc...
名字
姓
用户名
1.
名称0
奥托
@mdo
2.
名称1
桑顿
@肥
3.
姓名2
桑顿
@肥
问题的第二部分是简单的JSX:
<tr>
<th></th>
<th>First Name</th>
<th>Last Name</th>
<th>Username</th>
</tr>
</thead>
<tbody>
<tr>
<td>1</td>
<td>{this.state.teamRank[0]}</td>
<td>Otto</td>
<td>@mdo</td>
</tr>
<tr>
<td>2</td>
<td>{this.state.teamRank[1]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr><tr>
<td>3</td>
<td>{this.state.teamRank[2]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr>
您需要创建一个新对象作为您的新状态,然后将状态设置为此新对象,如下所示 由于不创建新数组,因此可以使用forEach而不是map
let newState = {}
element.teamRecords.forEach((element2,index) => {
const teamNames = element2.team.name;
const rankAndTeam = teamNames + index;
console.log(rankAndTeam);
// this will add a key of index (0,1,2,3...) with the team name as value
newState[index] = teamNames
});
this.setState({ teamRank: newState})
在组件中,可以循环对象的关键帧并渲染信息
在这里,您正在创建一个tr数组,它的React将处理此问题并正确渲染它
// rank will be (0,1,2,3...)
{Object.keys(this.state.teamRank).map(rank => (
<tr>
<td>{rank + 1}</td>
<td>{this.state.teamRank[rank]}</td>
<td>Otto</td>
<td>@mdo</td>
</tr>
))}
data2.records数组包含4个对象。在每个对象中都有teamRecords数组,该数组本身包含8个对象
考虑到您只想显示前8条记录。你有两个选择
您需要让数组处于状态,而不是对象
this.state = {
teamRank: []
}
选择1
创建一个数组,推送该数组中的每个名称,最后将该数组存储为state
let teamRank = [];
data2.records.map((element,ind)=>{
element.teamRecords.map((element2,index) => {
const teamNames = element2.team.name;
const rankAndTeam = teamNames + index;
console.log(rankAndTeam);
teamRank.push(teamNames)
});
})
this.setState({teamRank}, ()=>console.log(this.state.teamRank))
你可以打印出这样的名字
<tbody>
<tr>
<td>1</td>
<td>{ this.state.teamRank && this.state.teamRank[0]}</td>
<td>Otto</td>
<td>@mdo</td>
</tr>
<tr>
<td>2</td>
<td>{ this.state.teamRank && this.state.teamRank[1]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr><tr>
<td>3</td>
<td>{ this.state.teamRank && this.state.teamRank[2]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr>
</tbody>
你可以打印名字,比如
<tbody>
<tr>
<td>1</td>
<td>{ this.state.teamRank[0] && this.state.teamRank[0][0]}</td>
<td>Otto</td>
<td>@mdo</td>
</tr>
<tr>
<td>2</td>
<td>{ this.state.teamRank[0] && this.state.teamRank[0][1]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr><tr>
<td>3</td>
<td>{ this.state.teamRank[0] && this.state.teamRank[0][2]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr>
</tbody>
不准确的this.state.teamRank[1]登录未定义的对象
let teamRank = data2.records.map((element,ind)=>{
return element.teamRecords.map((element2,index) => { //Notice the return
const teamNames = element2.team.name;
const rankAndTeam = teamNames + index;
console.log(rankAndTeam);
return teamNames; //Notice the return
});
})
this.setState({teamRank}, ()=>console.log(this.state.teamRank))
<tbody>
<tr>
<td>1</td>
<td>{ this.state.teamRank[0] && this.state.teamRank[0][0]}</td>
<td>Otto</td>
<td>@mdo</td>
</tr>
<tr>
<td>2</td>
<td>{ this.state.teamRank[0] && this.state.teamRank[0][1]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr><tr>
<td>3</td>
<td>{ this.state.teamRank[0] && this.state.teamRank[0][2]}</td>
<td>Thornton</td>
<td>@fat</td>
</tr>
</tbody>