Javascript 如何在回调函数中正确访问数组值？

我试图在循环内的函数中正确访问IDs[I]的值。我试过以下方法

我认为这个方法将ID记录为字符串。我试图用索引访问它，但结果是未定义的。请参阅SimpleWithTrPrice函数调用中的console.log

for(i=0; i<IDs.length; i++)
        {   
            console.log("Outside of function Vendor is " + IDs[i]);//logs correctly
            var optionSelectionArray = currentlySelectedAttributes(IDs[i]);
            simpleWithAttrPrice(optionSelectionArray, function(data) {
                //var vendor = IDs[i];
                var basePrice = parseFloat(roundDollar(data));
                //newPriceArray[vendor][colorSelected]=basePrice;
                console.log("Vendor is " + IDs);//"5,3"
                console.log("Vendor is " + IDs[i]);//undefined
                $j('.details'+IDs[i]+ ' .priceBlock').empty();      
                $j('.details'+IDs[i]+ ' .priceBlock').append('<span>'+formatCurrency(basePrice,"$")+'</span>');

            });
        }

---

（i=0；i@Toby Allen谢谢！您对该链接的权利。此链接仅供参考：

function sendRequest(i) {
            var optionSelectionArray = currentlySelectedAttributes(IDs[i]);
            simpleWithAttrPrice(optionSelectionArray, function(data) {
                //var vendor = IDs[i];
                var basePrice = parseFloat(roundDollar(data));
                //newPriceArray[vendor][colorSelected]=basePrice;
                console.log("Vendor is " + IDs);//"5,3"
                console.log("Vendor is " + IDs[i]);//undefined
                $j('.details'+IDs[i]+ ' .priceBlock').empty();      
                $j('.details'+IDs[i]+ ' .priceBlock').append('<span>'+formatCurrency(basePrice,"$")+'</span>');
            });
        }//end sendRequest

        for(i=0; i<IDs.length; i++)
        {   
            sendRequest(i);
        }

函数发送请求（i）{
var OptionSelectionAry=当前选定属性（ID[i]）；
simpleWithAttrPrice（选项选择光线、函数（数据）{
//var供应商=IDs[i]；
var basePrice=parseFloat（整数美元（数据））；
//newPriceArray[vendor][colorSelected]=基准价格；
console.log（“供应商为”+IDs）；/“5,3”
console.log（“供应商是”+IDs[i]）；//未定义
$j（'.details'+IDs[i]+'.priceBlock'）.empty（）；
$j（'.details'+IDs[i]+'.priceBlock'）.append（''+formatCurrency（basePrice，“$”）+''）；
});
}//结束发送请求
对于（i=0；i确定和替代项。这是JavaScriptAppable duplicate中的一个常见问题：。基本上，所有回调都在
for
循环终止后运行，此时
i
处于其终值。当每个回调运行时，回调都会查找作用域链以查找
i
，并且每个回调都会找到相同的
i值。
for(i=0; i<IDs.length; i++)
        {   
            var vendor = IDs[i];
            var optionSelectionArray = currentlySelectedAttributes(vendor);
            simpleWithAttrPrice(optionSelectionArray, function(data) {
                var basePrice = parseFloat(roundDollar(data));
                //newPriceArray[vendor][colorSelected]=basePrice;
                console.log("Vendor is " + vendor); //only logs this once.
                $j('.details'+vendor+ ' .priceBlock').empty();//If I take this away, appends both prices to same block      
                $j('.details'+vendor+ ' .priceBlock').append('<span>'+formatCurrency(basePrice,"$")+'</span>');

            });
        }

function sendRequest(i) {
            var optionSelectionArray = currentlySelectedAttributes(IDs[i]);
            simpleWithAttrPrice(optionSelectionArray, function(data) {
                //var vendor = IDs[i];
                var basePrice = parseFloat(roundDollar(data));
                //newPriceArray[vendor][colorSelected]=basePrice;
                console.log("Vendor is " + IDs);//"5,3"
                console.log("Vendor is " + IDs[i]);//undefined
                $j('.details'+IDs[i]+ ' .priceBlock').empty();      
                $j('.details'+IDs[i]+ ' .priceBlock').append('<span>'+formatCurrency(basePrice,"$")+'</span>');
            });
        }//end sendRequest

        for(i=0; i<IDs.length; i++)
        {   
            sendRequest(i);
        }