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Javascript 使用Node.js将文件系统中的目录结构转换为JSON_Javascript_Node.js_D3.js_Filesystems - Fatal编程技术网

Javascript 使用Node.js将文件系统中的目录结构转换为JSON

Javascript 使用Node.js将文件系统中的目录结构转换为JSON,javascript,node.js,d3.js,filesystems,Javascript,Node.js,D3.js,Filesystems,我的文件结构如下: root |_ fruits |___ apple |______images |________ apple001.jpg |________ apple002.jpg |_ animals |___ cat |______images |________ cat001.jpg |________ cat002.jpg 我想使用Javascript和Node.js,监听这个根目录和所有子目录,并创建一个JSON来镜像这个目录结构,每个节点都包含类型、名称、路径和子目录:

我的文件结构如下:

root
|_ fruits
|___ apple
|______images
|________ apple001.jpg
|________ apple002.jpg
|_ animals
|___ cat
|______images
|________ cat001.jpg
|________ cat002.jpg
我想使用Javascript和Node.js,监听这个根目录和所有子目录,并创建一个JSON来镜像这个目录结构,每个节点都包含类型、名称、路径和子目录:

data = [
  {
    type: "folder",
    name: "animals",
    path: "/animals",
    children: [
      {
        type: "folder",
        name: "cat",
        path: "/animals/cat",
        children: [
          {
            type: "folder",
            name: "images",
            path: "/animals/cat/images",
            children: [
              {
                type: "file",
                name: "cat001.jpg",
                path: "/animals/cat/images/cat001.jpg"
              }, {
                type: "file",
                name: "cat001.jpg",
                path: "/animals/cat/images/cat002.jpg"
              }
            ]
          }
        ]
      }
    ]
  }
];
下面是一个coffeescript JSON:

data = 
[
  type: "folder"
  name: "animals"
  path: "/animals"
  children  :
    [
      type: "folder"
      name: "cat"
      path: "/animals/cat"
      children:
        [
          type: "folder"
          name: "images"
          path: "/animals/cat/images"
          children: 
            [
              type: "file"
              name: "cat001.jpg"
              path: "/animals/cat/images/cat001.jpg"
            , 
              type: "file"
              name: "cat001.jpg"
              path: "/animals/cat/images/cat002.jpg"
            ]
        ]
    ]
]

如何在django视图中获取此json数据格式?(python)

这里是一个草图。错误处理留给读者作为练习

var fs = require('fs'),
    path = require('path')

function dirTree(filename) {
    var stats = fs.lstatSync(filename),
        info = {
            path: filename,
            name: path.basename(filename)
        };

    if (stats.isDirectory()) {
        info.type = "folder";
        info.children = fs.readdirSync(filename).map(function(child) {
            return dirTree(filename + '/' + child);
        });
    } else {
        // Assuming it's a file. In real life it could be a symlink or
        // something else!
        info.type = "file";
    }

    return info;
}

if (module.parent == undefined) {
    // node dirTree.js ~/foo/bar
    var util = require('util');
    console.log(util.inspect(dirTree(process.argv[2]), false, null));
}

您可以使用此项目中的代码,但应根据需要调整代码:

发件人:

致:

做:

new File ("a").list (function (error, files){
    //files...
});
我的CS示例(w/express)基于Miika的解决方案:

fs = require 'fs' #file system module
path = require 'path' # file path module

# returns json tree of directory structure
tree = (root) ->
    # clean trailing '/'(s)
    root = root.replace /\/+$/ , ""
    # extract tree ring if root exists
    if fs.existsSync root
        ring = fs.lstatSync root
    else
        return 'error: root does not exist'
    # type agnostic info
    info = 
        path: root
        name: path.basename(root)
    # dir   
    if ring.isDirectory()
        info.type = 'folder'
        # execute for each child and call tree recursively
        info.children = fs.readdirSync(root) .map (child) ->
            tree root + '/' + child
    # file
    else if ring.isFile()
        info.type = 'file'
    # link
    else if ring.isSymbolicLink()
        info.type = 'link'
    # other
    else
        info.type = 'unknown'
    # return tree 
    info

# error handling
handle = (e) ->
    return 'uncaught exception...'

exports.index = (req, res) ->
    try
        res.send tree './test/'
    catch e
        res.send handle e
 function list(dir) {
   const walk = entry => {
     return new Promise((resolve, reject) => {
       fs.exists(entry, exists => {
         if (!exists) {
           return resolve({});
         }
         return resolve(new Promise((resolve, reject) => {
           fs.lstat(entry, (err, stats) => {
             if (err) {
               return reject(err);
             }
             if (!stats.isDirectory()) {
               return resolve({
                 // path: entry,
                 // type: 'file',
                 name: path.basename(entry),
                 time: stats.mtime,
                 size: stats.size
               });
             }
             resolve(new Promise((resolve, reject) => {
               fs.readdir(entry, (err, files) => {
                 if (err) {
                   return reject(err);
                 }
                 Promise.all(files.map(child => walk(path.join(entry, child)))).then(children => {
                   resolve({
                     // path: entry,
                     // type: 'folder',
                     name: path.basename(entry),
                     time: stats.mtime,
                     entries: children
                   });
                 }).catch(err => {
                   reject(err);
                 });
               });
             }));
           });
         }));
       });
     });
   }

   return walk(dir);
 }

公认的答案是有效的,但它是同步的,会严重影响您的性能,尤其是对于大型目录树。
我强烈建议您使用以下异步解决方案,它既快速又无阻塞。
基于并行求解

用法示例:

var dirTree = ('/path/to/dir');

diretoryTreeToObj(dirTree, function(err, res){
    if(err)
        console.error(err);

    console.log(JSON.stringify(res));
});

它有一个NPM模块

创建表示目录树的对象

发件人:

致:

用法 您还可以按扩展进行筛选:

var filteredTree = directoryTree('/some/path', ['.jpg', '.png']);

在本例中,我使用了“walk”lib,它获取您的根路径,递归地遍历文件和目录,并发出一个directory/file事件,其中包含您从节点需要的所有信息, 检查该实现-->


以下是一个异步解决方案:

fs = require 'fs' #file system module
path = require 'path' # file path module

# returns json tree of directory structure
tree = (root) ->
    # clean trailing '/'(s)
    root = root.replace /\/+$/ , ""
    # extract tree ring if root exists
    if fs.existsSync root
        ring = fs.lstatSync root
    else
        return 'error: root does not exist'
    # type agnostic info
    info = 
        path: root
        name: path.basename(root)
    # dir   
    if ring.isDirectory()
        info.type = 'folder'
        # execute for each child and call tree recursively
        info.children = fs.readdirSync(root) .map (child) ->
            tree root + '/' + child
    # file
    else if ring.isFile()
        info.type = 'file'
    # link
    else if ring.isSymbolicLink()
        info.type = 'link'
    # other
    else
        info.type = 'unknown'
    # return tree 
    info

# error handling
handle = (e) ->
    return 'uncaught exception...'

exports.index = (req, res) ->
    try
        res.send tree './test/'
    catch e
        res.send handle e
 function list(dir) {
   const walk = entry => {
     return new Promise((resolve, reject) => {
       fs.exists(entry, exists => {
         if (!exists) {
           return resolve({});
         }
         return resolve(new Promise((resolve, reject) => {
           fs.lstat(entry, (err, stats) => {
             if (err) {
               return reject(err);
             }
             if (!stats.isDirectory()) {
               return resolve({
                 // path: entry,
                 // type: 'file',
                 name: path.basename(entry),
                 time: stats.mtime,
                 size: stats.size
               });
             }
             resolve(new Promise((resolve, reject) => {
               fs.readdir(entry, (err, files) => {
                 if (err) {
                   return reject(err);
                 }
                 Promise.all(files.map(child => walk(path.join(entry, child)))).then(children => {
                   resolve({
                     // path: entry,
                     // type: 'folder',
                     name: path.basename(entry),
                     time: stats.mtime,
                     entries: children
                   });
                 }).catch(err => {
                   reject(err);
                 });
               });
             }));
           });
         }));
       });
     });
   }

   return walk(dir);
 }
请注意,当目录不存在时,将返回一个空结果,而不是抛出一个错误

以下是一个示例结果:

{
    "name": "root",
    "time": "2017-05-09T07:46:26.740Z",
    "entries": [
        {
            "name": "book.txt",
            "time": "2017-05-09T07:24:18.673Z",
            "size": 0
        },
        {
            "name": "cheatsheet-a5.pdf",
            "time": "2017-05-09T07:24:18.674Z",
            "size": 262380
        },
        {
            "name": "docs",
            "time": "2017-05-09T07:47:39.507Z",
            "entries": [
                {
                    "name": "README.md",
                    "time": "2017-05-08T10:02:09.651Z",
                    "size": 19229
                }
            ]
        }
    ]
}
这将是:

root
|__ book.txt
|__ cheatsheet-a5.pdf
|__ docs
      |__ README.md

这在第1层非常有效,但是,子对象看起来像:children:[Object]。。。你看到什么问题了吗?是的。创建的对象很好,但默认情况下,console.log仅打印有限深度的对象。我编辑了代码来打印完整的树。谢谢你的func。我想最好使用path.join而不是
a+'/'+b
<代码>返回目录树(path.join(filename,child))如何对输出进行排序,使目录先出现(按字母顺序),然后是文件(也按字母顺序)?@peterButcher如果以树结构打印,您会如何排序?但是您可以使用lodash来构造返回的对象。。它只是一个普通对象,所以请像对其他对象一样对其进行排序:)我从github中删除了该项目。这个链接是一个叉。@Gabriellamas为什么要从github中删除它?对我来说,这似乎是一个相当有用的项目。这是获取d3.js层次数据的常见要求。我想用d3.js标记这个问题,但堆栈溢出最多允许5个:(我希望这些答案中的一个能够从stdin中读取路径,这样你就可以将路径列表转换成json对象,比如:
find | paths2json
。这将通过管道充分利用Unix的可组合性。这正是我所需要的。谢谢。它工作得很好。小尼:你在diretorytreetobj中有一个输入错误,我想nk应该是directoryTreeToObj否?
var filteredTree = directoryTree('/some/path', ['.jpg', '.png']);
const walk = require('walk');

class FsTree {

    constructor(){

    }

    /**
     * @param rootPath
     * @returns {Promise}
     */
    getFileSysTree(rootPath){
        return new Promise((resolve, reject)=>{

            const root = rootPath || __dirname; // if there's no rootPath use exec location
            const tree = [];
            const nodesMap = {};
            const walker  = walk.walk(root, { followLinks: false}); // filter doesn't work well

            function addNode(node, path){
                if ( node.name.indexOf('.') === 0 || path.indexOf('/.') >= 0){ // ignore hidden files
                    return;
                }
                var relativePath = path.replace(root,'');

                node.path = relativePath + '/' + node.name;
                nodesMap[node.path] = node;

                if ( relativePath.length === 0 ){ //is root
                    tree.push(node);
                    return;
                }
                node.parentPath = node.path.substring(0,node.path.lastIndexOf('/'));
                const parent = nodesMap[node.parentPath];
                parent.children.push(node);

            }

            walker.on('directory', (path, stats, next)=>{
                addNode({ name: stats.name, type:'dir',children:[]}, path);
                next();
            });

            walker.on('file', (path,stats,next)=>{
                addNode({name:stats.name, type:'file'},path);
                next();
            });

            walker.on('end',()=>{
                resolve(tree);
            });

            walker.on('errors',  (root, nodeStatsArray, next) => {
                reject(nodeStatsArray);
                next();
            });
        });

    }
}


const fsTreeFetcher = new FsTree();

fsTreeFetcher.getFileSysTree(__dirname).then((result)=>{
    console.log(result);
});
 function list(dir) {
   const walk = entry => {
     return new Promise((resolve, reject) => {
       fs.exists(entry, exists => {
         if (!exists) {
           return resolve({});
         }
         return resolve(new Promise((resolve, reject) => {
           fs.lstat(entry, (err, stats) => {
             if (err) {
               return reject(err);
             }
             if (!stats.isDirectory()) {
               return resolve({
                 // path: entry,
                 // type: 'file',
                 name: path.basename(entry),
                 time: stats.mtime,
                 size: stats.size
               });
             }
             resolve(new Promise((resolve, reject) => {
               fs.readdir(entry, (err, files) => {
                 if (err) {
                   return reject(err);
                 }
                 Promise.all(files.map(child => walk(path.join(entry, child)))).then(children => {
                   resolve({
                     // path: entry,
                     // type: 'folder',
                     name: path.basename(entry),
                     time: stats.mtime,
                     entries: children
                   });
                 }).catch(err => {
                   reject(err);
                 });
               });
             }));
           });
         }));
       });
     });
   }

   return walk(dir);
 }
{
    "name": "root",
    "time": "2017-05-09T07:46:26.740Z",
    "entries": [
        {
            "name": "book.txt",
            "time": "2017-05-09T07:24:18.673Z",
            "size": 0
        },
        {
            "name": "cheatsheet-a5.pdf",
            "time": "2017-05-09T07:24:18.674Z",
            "size": 262380
        },
        {
            "name": "docs",
            "time": "2017-05-09T07:47:39.507Z",
            "entries": [
                {
                    "name": "README.md",
                    "time": "2017-05-08T10:02:09.651Z",
                    "size": 19229
                }
            ]
        }
    ]
}
root
|__ book.txt
|__ cheatsheet-a5.pdf
|__ docs
      |__ README.md