Javascript 弹出提交请求后,是否应打开父窗口?
从父窗口我打开一个弹出窗口。在弹出屏幕控件成功后,应该转到父窗口,但当我尝试下面的代码时,父窗口将首先出现,子窗口将位于该屏幕后面Javascript 弹出提交请求后,是否应打开父窗口?,javascript,jquery,Javascript,Jquery,从父窗口我打开一个弹出窗口。在弹出屏幕控件成功后,应该转到父窗口,但当我尝试下面的代码时,父窗口将首先出现,子窗口将位于该屏幕后面 function A(requestId) { //strong text B();//it will open child window c(); //after this i am trying to open parent window by calling this method here. } 函数B(){ var childWind
function A(requestId)
{ //strong text
B();//it will open child window
c(); //after this i am trying to open parent window by calling this method here.
}
函数B(){
var childWindowId=“v”
请帮我解决这个问题
function myFunction() {var myWindow = window.open("", "", "width=200,height=100");
函数myFunction(){var myWindow=window.open(“,”,“width=200,height=100”);
可以粘贴保存用户定义函数B()和C()的代码块吗?为什么不关闭子窗口?如果我关闭子窗口,它将不会转到下一个父页面
function myFunction() {var myWindow = window.open("", "", "width=200,height=100");