Javascript Sequelize-基于特定属性包含
我有一个定义如下的模型:Javascript Sequelize-基于特定属性包含,javascript,sql,node.js,postgresql,sequelize.js,Javascript,Sql,Node.js,Postgresql,Sequelize.js,我有一个定义如下的模型: sequelize.define('game', { id: { type: type.INTEGER, primaryKey: true, autoIncrement: true, }, leaderId: { type: type.INTEGER, allowNull: false, references: { model:
sequelize.define('game', {
id: {
type: type.INTEGER,
primaryKey: true,
autoIncrement: true,
},
leaderId: {
type: type.INTEGER,
allowNull: false,
references: {
model: 'users',
key: 'id',
},
},
playerId: {
type: type.INTEGER,
allowNull: false,
references: {
model: 'users',
key: 'id',
},
},
status: {
type: type.STRING,
defaultValue: 'running',
},
notes: {
type: type.TEXT,
},
});
我正在尝试使用Sequelize加载所有游戏
对象,并包含id等于玩家id
字段的用户
问题是我有两个属性(leaderId
,playerId
),它们引用了用户
模型,因此按如下方式使用包含
不起作用:
Game.findAll({
where: conditions,
include: [{ model: User }],
})
是否有方法指定include
命令应该使用哪个属性
const game = sequelize.define('game', {
id: {
type: type.INTEGER,
primaryKey: true,
autoIncrement: true,
},
leaderId: {
type: type.INTEGER,
allowNull: false,
references: {
model: 'users',
key: 'id',
},
},
playerId: {
type: type.INTEGER,
allowNull: false,
references: {
model: 'users',
key: 'id',
},
as:'player'
},
status: {
type: type.STRING,
defaultValue: 'running',
},
notes: {
type: type.TEXT,
},
});
game.associate = function (models) {
game.belongsTo(models.user, {
foreignKey: "playerId",
as: "player",
});
game.belongsTo(models.user, {
foreignKey: "leaderId",
as: "leader",
});
};
Game.findAll({
where: conditions,
include: ['player'],
})
Or
Game.findAll({
where: conditions,
include: [{model: User, as: 'player' }],
})
Or
Game.findAll({
where: conditions,
include: [{model: User, as: 'player', foreignKey: 'playerId' }],
})