Javascript 基于与特定属性值匹配的另一个对象数组删除数组中的对象

我有两个数组（如下）-我想修改

relatedCards

数组，使其不包括

ownedCards

数组中存在的对象，其中

relatedCards.series

和

ownedCards.series

的值与

relatedCards.card\u number

的值相同

let relatedCards = [
   {
      "brand":"National Treasures",
      "card_number":"43",
      "manufacturer":"Panini",
      "series":"Rookie Patch Autographs",
      "year":"2017"
   },
   {
      "brand":"National Treasures",
      "card_number":"4",
      "manufacturer":"Panini",
      "series":"2014 National Notable Nicknames",
      "year":"2017"
   },
   {
      "brand":"National Treasures",
      "card_number":"99",
      "manufacturer":"Panini",
      "series":"Collegiate Materials Signatures Silver",
      "year":"2017"
   },
   {
      "brand":"National Treasures",
      "card_number":"199",
      "manufacturer":"Panini",
      "series":"Collegiate Materials Signatures Silver",
      "year":"2017"
   }
]


let ownedCards = [
   {
      "brand":"National Treasures",
      "card_number":"43",
      "manufacturer":"Panini",
      "series":"Rookie Patch Autographs",
      "year":"2017"
   },
   {
      "brand":"National Treasures",
      "card_number":"4",
      "manufacturer":"Panini",
      "series":"2014 National Notable Nicknames",
      "year":"2017"
   },
   {
      "brand":"National Treasures",
      "card_number":"411",
      "manufacturer":"Panini",
      "series":"Collegiate Materials",
      "year":"2017"
   }
]

基于以上两个数组，新数组的输出应为

[   
   {
      "brand":"National Treasures",
      "card_number":"99",
      "manufacturer":"Panini",
      "series":"Collegiate Materials Signatures Silver",
      "year":"2017"
   },
   {
      "brand":"National Treasures",
      "card_number":"199",
      "manufacturer":"Panini",
      "series":"Collegiate Materials Signatures Silver",
      "year":"2017"
   }
]

---

实现这一点最有效的方法是什么？

最简单的方法是使用

过滤器和
一些


let related cards=[{“品牌”：“国宝”，“卡号”：“43”，“制造商”：“帕尼尼”，“系列”：“新人补丁签名”，“年份”：“2017”}，{“品牌”：“国宝”，“卡号”：“4”，“制造商”：“帕尼尼”，“系列”：“2014年全国著名昵称”，“年份”：“2017”}，{“品牌”：“国宝”，“卡号”：“99”，“制造商”：“帕尼尼”，“系列”：“学院材料签名银牌”，“年份”：“2017”}，{“品牌”：“国宝”，“卡号”：“199”，“制造商”：“帕尼尼”，“系列”：“学院材料签名银牌”，“年份”：“2017”}]；自有卡片=[{“品牌”：“国宝”，“卡号”：“43”，“制造商”：“帕尼尼”，“系列”：”新秀贴片签名，“年份”：“2017”}，{“品牌”：“国宝”，“卡号”：“4”，“制造商”：“帕尼尼”，“系列”：“2014年全国著名昵称”，“年份”：“2017”}，{“品牌”：“国宝”，“卡号”：“411”，“制造商”：“帕尼尼”，“系列”：“学院材料”，“年份”：“2017”}；
设res=relatedCards.filter（x=>！ownedCards）
.一些（y=>y.card_number===x.card_number&&y.series==x.series））；
console.log（res）；
那么这些都没有任何帮助？