Javascript 从Ajax请求向PHP发布多个值

我有一个Ajax请求从JavaScript保存数据，并使用单独的（“saveData.php”）php文件将其写入文件。我想知道是否可以在同一个Ajax请求中“发布”多个JavaScript变量/字符串

例如，我目前有：

function saveData(){ //sends an AJAX request to saveData.php
$.ajax({
    type: "POST",
    url: "saveData.php",
    dataType: "text/plain",
    ContentType: "charset=utf-8",
    data: {"data": dataString},
  })
}

通过我的PHP文件，这非常有效，如下代码所示：

$data = $_POST["data"];
$theFile = fopen("Data/" . FileNameHere . ".txt", "a+");

// Save data into a file based on their username
fwrite($theFile, $data);
fclose($theFile);   

但是我想基于他们的userID保存文件，userID是一个JavaScript变量

我可以这样做吗：

function saveData(){ //sends an AJAX request to saveData.php
$.ajax({
    type: "POST",
    url: "saveData.php",
    dataType: "text/plain",
    ContentType: "charset=utf-8",
    data: {"data": dataString},
    data1: {"data1": userID},   <-----new line with JS variable 'userID'
  })
}

// Prepare line of data to save.
$data = $_POST["data"];
$userID = $_POST["data1"];     <--------New code to POST "data1" from Ajax
$theFile = fopen("Data/" . $userID . ".txt", "a+");

// Save data into a file based on their username
fwrite($theFile, $data);
fclose($theFile);   

$data = $_POST["data"];
$userID = $_POST["data2"];
$theFile = fopen("Data/" . $userID . ".txt", "a+");

// Save data into a file based on their username
fwrite($theFile, $data);
fclose($theFile);

函数saveData（）{//向saveData.php发送一个AJAX请求
$.ajax({
类型：“POST”，
url:“saveData.php”，
数据类型：“文本/普通”，
ContentType:“字符集=utf-8”，
数据：{“数据”：数据字符串}，
data1:{“data1”：userID}，是的，您可以，您正在传递一个JSON对象，以便它可以具有任意多的属性

了解有关如何在服务器端发送多个数据的更多信息。
试试这个

function saveData(){ //sends an AJAX request to saveData.php
$.ajax({
    type: "POST",
    url: "saveData.php",
    dataType: "text/plain",
    ContentType: "charset=utf-8",
    data: {
            "data": dataString, 
            "data2":val2,
            "data3":val3,
            "data4":val4
          },
  })
}

PHP文件如下所示：

function saveData(){ //sends an AJAX request to saveData.php
$.ajax({
    type: "POST",
    url: "saveData.php",
    dataType: "text/plain",
    ContentType: "charset=utf-8",
    data: {"data": dataString},
    data1: {"data1": userID},   <-----new line with JS variable 'userID'
  })
}

// Prepare line of data to save.
$data = $_POST["data"];
$userID = $_POST["data1"];     <--------New code to POST "data1" from Ajax
$theFile = fopen("Data/" . $userID . ".txt", "a+");

// Save data into a file based on their username
fwrite($theFile, $data);
fclose($theFile);   

$data = $_POST["data"];
$userID = $_POST["data2"];
$theFile = fopen("Data/" . $userID . ".txt", "a+");

// Save data into a file based on their username
fwrite($theFile, $data);
fclose($theFile);

是的，您可以，您正在传递一个JSON对象，以便它可以具有任意多的属性

了解有关如何在服务器端发送多个数据的更多信息。
试试这个

function saveData(){ //sends an AJAX request to saveData.php
$.ajax({
    type: "POST",
    url: "saveData.php",
    dataType: "text/plain",
    ContentType: "charset=utf-8",
    data: {
            "data": dataString, 
            "data2":val2,
            "data3":val3,
            "data4":val4
          },
  })
}

PHP文件如下所示：

function saveData(){ //sends an AJAX request to saveData.php
$.ajax({
    type: "POST",
    url: "saveData.php",
    dataType: "text/plain",
    ContentType: "charset=utf-8",
    data: {"data": dataString},
    data1: {"data1": userID},   <-----new line with JS variable 'userID'
  })
}

// Prepare line of data to save.
$data = $_POST["data"];
$userID = $_POST["data1"];     <--------New code to POST "data1" from Ajax
$theFile = fopen("Data/" . $userID . ".txt", "a+");

// Save data into a file based on their username
fwrite($theFile, $data);
fclose($theFile);   

$data = $_POST["data"];
$userID = $_POST["data2"];
$theFile = fopen("Data/" . $userID . ".txt", "a+");

// Save data into a file based on their username
fwrite($theFile, $data);
fclose($theFile);

它是JSON。阅读（或其他教程）更多阅读：它是JSON。阅读（或其他教程）更多阅读：我很高兴能帮助你。希望你不反对我在你的文章中增加一点内容answer@RiggsFolly不，我没有。如果你想添加更多信息，请随意添加。@Phoenix404我需要帮助。我想知道我是否可以向你寻求帮助？是的，当然……我很乐意帮助你。希望你不反对我向你的网站添加一点信息answer@RiggsFol不，我没有。如果您想添加更多信息，请随意添加。@Phoenix404我需要帮助。我想知道是否可以向您寻求帮助？是的，当然……请继续