Javascript 表单重新加载页面而不在提交时发送数据
这是我的密码 在my.js文件中:Javascript 表单重新加载页面而不在提交时发送数据,javascript,php,jquery,html,forms,Javascript,Php,Jquery,Html,Forms,这是我的密码 在my.js文件中: function Sendit() { bValidate = validateField(); if(bValidate) { var title = $("#title").val(); theUrl = 'index.php'; params = ''; params += 'action=Send'; params += '&tit
function Sendit()
{
bValidate = validateField();
if(bValidate)
{
var title = $("#title").val();
theUrl = 'index.php';
params = '';
params += 'action=Send';
params += '&title='+title;
$.ajax ({
url: theUrl,
data: params,
async:true,
success: function (data, textStatus)
{
//do smth
alert('went well');
}
,
error: function(jqXHR, textStatus, errorThrown)
{
alert(errorThrown);
}
});
}
}
function validateField()
{
var title = document.getElementById('title').value;
if(!title.match(/\S/))
{
//do some alerting
return false;
}
else
{
return true;
}
}
在我的index.php文件中:
<form action="" method="post" name="myform" id="myform"" >
Title: <input class="" type="text" name="title" value="" id="title"/> <br>
<input type="submit" value="Submit" onClick="javascript:Sendit();return false; ">
</form>
<?php
if ($_REQUEST["action"]=='Send')
{
$title = $_REQUEST["title"];
$sql = "INSERT INTO ...
$retval = $mysqli->query($sql, $conn);
if(! $retval ) {
echo('Could not enter data insert: ' . mysql_error());
}
else
{
//inform that everything went well
}
?>
您的validateField()
函数永远不会返回true,因此您的if(bValidate)
将永远不会运行。Javascript函数返回未定义,除非显式返回某些内容,请尝试以下操作:
function validateField()
{
var title = document.getElementById('title').value;
if(!title.match(/\S/))
{
//do some alerting
return false;
} esle {
return true;
}
}
您的validateField()
函数永远不会返回true,因此您的if(bValidate)
永远不会运行。Javascript函数返回未定义,除非显式返回某些内容,请尝试以下操作:
function validateField()
{
var title = document.getElementById('title').value;
if(!title.match(/\S/))
{
//do some alerting
return false;
} esle {
return true;
}
}
使用以下代码发送请求
function Sendit()
{
bValidate = validateField();
if(bValidate)
{
var title = $("#title").val();
theUrl = 'index.php';
params = {};
params["action"] = 'Send';
params["title"] = title;
$.ajax ({
url: theUrl,
data: params,
async:true,
success: function (data, textStatus)
{
//do smth
alert('went well');
}
,
error: function(jqXHR, textStatus, errorThrown)
{
alert(errorThrown);
}
});
}
}
使用以下代码发送请求
function Sendit()
{
bValidate = validateField();
if(bValidate)
{
var title = $("#title").val();
theUrl = 'index.php';
params = {};
params["action"] = 'Send';
params["title"] = title;
$.ajax ({
url: theUrl,
data: params,
async:true,
success: function (data, textStatus)
{
//do smth
alert('went well');
}
,
error: function(jqXHR, textStatus, errorThrown)
{
alert(errorThrown);
}
});
}
}
它不会改变一件事:(它不会改变一件事:(