Javascript 如果操作为真，则从OnPress更新状态

如果用户在AlertIOS窗口中按Yes，我会尝试将常数更新为true

但目前无法使其按其构建方式运行

deleteDeck = () => {
    const {id} = this.props
    const executeRemoval = false
    if (Platform.OS === 'ios') {
      AlertIOS.alert(
        'Remove Deck',
        'Are you sure you want to delete this deck?',
        [
          {text: 'Cancel', onPress: () => console.log('Cancel Pressed'), style: 'cancel'},
          {text: 'Yes', onPress: () =>  executeRemoval = true},
        ],
      )
    }

如果用户按Yes，const executemoval现在应该为true，并且通过输入

{executeRemoval &&
      removeDeck(id)
      .then(() =>  this.props.deleteDeck(id))
      .then(() =>  this.props.navigation.dispatch(NavigationActions.reset({
          index: 0,
          actions: [
            NavigationActions.navigate({ routeName: 'Home'})
          ]
        })))
      }

---

有人对如何让这个behvior工作有什么想法吗

您需要使用有状态组件并将ExecuteMoval的当前状态保存在其中

class yourClass extends Component {
    constructor(props){
        super(props);
        this.state = {
            executeRemoval = false
        }
    }
}

在onPress事件中，您可以执行以下操作：

onPress={() => this.setState({ executeRemoval: true })}

---

您需要使用有状态组件并在其中保存ExecuteMoval的当前状态

class yourClass extends Component {
    constructor(props){
        super(props);
        this.state = {
            executeRemoval = false
        }
    }
}

在onPress事件中，您可以执行以下操作：

onPress={() => this.setState({ executeRemoval: true })}

---

创建一个简单的函数，该函数将处理要运行的操作

示例

executeRemoval = () => {
  const { id } = this.props;
  removeDeck(id)
  .then(() =>  this.props.deleteDeck(id))
  .then(() =>  this.props.navigation.dispatch(NavigationActions.reset({
    index: 0,
    actions: [
      NavigationActions.navigate({ routeName: 'Home'})
    ]
  })))
}

deleteDeck = () => {
  if (Platform.OS === 'ios') {
    AlertIOS.alert(
      'Remove Deck',
      'Are you sure you want to delete this deck?',
      [
        {text: 'Cancel', onPress: () => console.log('Cancel Pressed'), style: 'cancel'},
        {text: 'Yes', onPress: this.executeRemoval },
      ],
    )
  }
}

---

创建一个简单的函数，该函数将处理要运行的操作

示例

executeRemoval = () => {
  const { id } = this.props;
  removeDeck(id)
  .then(() =>  this.props.deleteDeck(id))
  .then(() =>  this.props.navigation.dispatch(NavigationActions.reset({
    index: 0,
    actions: [
      NavigationActions.navigate({ routeName: 'Home'})
    ]
  })))
}

deleteDeck = () => {
  if (Platform.OS === 'ios') {
    AlertIOS.alert(
      'Remove Deck',
      'Are you sure you want to delete this deck?',
      [
        {text: 'Cancel', onPress: () => console.log('Cancel Pressed'), style: 'cancel'},
        {text: 'Yes', onPress: this.executeRemoval },
      ],
    )
  }
}