Javascript 当日期字符串位于另一个字符串中时格式化该字符串

我正试图找到一种方法，使用javascript格式化位于字符串内部的日期字符串

字符串可以是：

“你好，从2010-03-04 00:00:00.0到2010-03-31 00:00:00.0”

或

“像2010-03-0420:00:00.0和2010-03-3100:00:02.0之类的废话”

我希望它的结局是：

“像2010年3月4日和2010年3月31日之类的废话”

---

有人知道如何实现这一点吗？

我建议使用a来定位日期字符串，假设您知道现有格式，然后您可以将其替换为格式化版本。

我建议使用a来定位日期字符串，假设您知道现有格式，然后，您可以将其替换为格式化版本。

如果日期始终为该格式，则可以使用正则表达式替换它：

var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
str  = "hello there From 2010-03-04 00:00:00.0 to 2010-03-31 00:00:00.0";
alert(str.replace(/(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2})\:(\d{2}).(\d{1})/g,
    function ($0, $1, $2, $3, $4, $5, $6, $7, $8)
    {
        var date = new Date($1, $2, $3);
        return date.getDate() + " " + months[date.getMonth()] + " " + date.getFullYear();
    })
);

---

示例位于

如果日期始终是该格式，则可以使用正则表达式替换它：

var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
str  = "hello there From 2010-03-04 00:00:00.0 to 2010-03-31 00:00:00.0";
alert(str.replace(/(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2})\:(\d{2}).(\d{1})/g,
    function ($0, $1, $2, $3, $4, $5, $6, $7, $8)
    {
        var date = new Date($1, $2, $3);
        return date.getDate() + " " + months[date.getMonth()] + " " + date.getFullYear();
    })
);

举例