Javascript 如何计算键的值之和?
我有这样的收藏:Javascript 如何计算键的值之和?,javascript,jquery,collections,underscore.js,Javascript,Jquery,Collections,Underscore.js,我有这样的收藏: { "2.2": { "BALL":{"white":9,"black":11,"red":4}, "BAG":{"white":2,"black":11,"red":1}, "COVER":{"white":3,"black":8,"red":1} }, "2.3": { "BALL":{"white":1,"black":0,"red":7}, "BAG":{"whit
{
"2.2": {
"BALL":{"white":9,"black":11,"red":4},
"BAG":{"white":2,"black":11,"red":1},
"COVER":{"white":3,"black":8,"red":1}
},
"2.3": {
"BALL":{"white":1,"black":0,"red":7},
"BAG":{"white":3,"black":0,"red":0},
"COVER":{"white":9,"black":2,"red":28}
}
}
{
"2.2": {"white": 14, "black": 30, "red": 6},
"2.3": {"white": 13, "black": 2, "red": 35}
}
我想计算“2.2”和“2.3”的总颜色(白、黑、红)
输出
所需的输出应如下所示:
{
"2.2": {
"BALL":{"white":9,"black":11,"red":4},
"BAG":{"white":2,"black":11,"red":1},
"COVER":{"white":3,"black":8,"red":1}
},
"2.3": {
"BALL":{"white":1,"black":0,"red":7},
"BAG":{"white":3,"black":0,"red":0},
"COVER":{"white":9,"black":2,"red":28}
}
}
{
"2.2": {"white": 14, "black": 30, "red": 6},
"2.3": {"white": 13, "black": 2, "red": 35}
}
我尝试过使用下划线.map
函数,但无法正确理解它。任何人都可以帮忙?
PS:需要仅使用下划线.js的解决方案。尝试:
var obj = {
"2.2": {
"BALL": {
"white": 9, "black": 11, "red": 4
},
"BAG": {
"white": 2, "black": 11, "red": 1
},
"COVER": {
"white": 3, "black": 8, "red": 1
}
},
"2.3": {
"BALL": {
"white": 1, "black": 0, "red": 7
},
"BAG": {
"white": 3, "black": 0, "red": 0
},
"COVER": {
"white": 9, "black": 2, "red": 28
}
}
}
var w = 0;
for(var i in obj){
for(var j in obj[i]){
w +=obj[i][j]['white'];
}
}
更新:
var obj = {
"2.2": {
"BALL": {
"white": 9, "black": 11, "red": 4
},
"BAG": {
"white": 2, "black": 11, "red": 1
},
"COVER": {
"white": 3, "black": 8, "red": 1
}
},
"2.3": {
"BALL": {
"white": 1, "black": 0, "red": 7
},
"BAG": {
"white": 3, "black": 0, "red": 0
},
"COVER": {
"white": 9, "black": 2, "red": 28
}
}
}
for (var i in obj) {
var tmp = {
white: 0,
black: 0,
red: 0
};
for (var j in obj[i]) {
tmp['white'] += obj[i][j]['white'];
tmp['black'] += obj[i][j]['black'];
tmp['red'] += obj[i][j]['red'];
}
obj[i] = tmp
}
console.log(obj);
下面是下划线.js
解决方案
_.mapObject(collections, function(collection) {
return _.reduce(collection, function(memo, col) {
// credit: Bergi on http://stackoverflow.com/a/17350790/1465828
// the following line reads:
// for (var p in col) => loop all properties in col
// memo[p] = ... => assign memo[p] as ...
// (p in memo ? memo[p] : 0) => IF property p exists in memo, then memo[p], otherwise 0
// + col[p] => add col's p
for (var p in col) { memo[p] = (p in memo ? memo[p] : 0) + col[p]; }
return memo;
}, {});
});
关于“2.2”和“2.3”,你所说的“关于”是什么意思?你想要两个和吗?一个简单的解决方案是在嵌套迭代中进行。2.2和2.3的外部迭代和内部迭代计算白色的总和…请检查编辑的问题。对不起,我没有很好地解释。你的解决办法是把所有的白色相加。请检查我提到的期望输出。Thanks@ahmadhamza已经进行了更新,以获得您稍后添加的输出。非常感谢。我已经将其标记为已接受答案,尽管它没有使用下划线.js方法。我使用mapObject
函数得到类型错误。你知道为什么吗?请问你使用的是哪个版本的\uuujs
?我可以在map
中找到mapObject
用于数组,而mapObject
用于对象。最新版本是1.8.3,我查看了1.7.0源代码,发现还没有mapObject
。所以,我的解决方案不适用于v1.7.0。备忘录中的p是什么?