Javascript 对通过JQuery追加的HTML表进行排序
您好,我正在尝试使用Tablesorter()对通过JQuery.appends生成的表进行排序。这就是我的代码的外观:Javascript 对通过JQuery追加的HTML表进行排序,javascript,jquery,tablesorter,Javascript,Jquery,Tablesorter,您好,我正在尝试使用Tablesorter()对通过JQuery.appends生成的表进行排序。这就是我的代码的外观: $(document).ready(function() { *Lotsa more code .....* $.get("../skillqueue",{keyid: keyid, charid: charid},function(xmlskillqueue){ console.log("XML Skillqueue"); console.
$(document).ready(function() {
*Lotsa more code .....*
$.get("../skillqueue",{keyid: keyid, charid: charid},function(xmlskillqueue){
console.log("XML Skillqueue");
console.log(xmlskillqueue);
//Variables for
var rowsets = xmlskillqueue.getElementsByTagName("rowset");
var skillrows;
for(var i = 0; i < rowsets.length; i++){
if(rowsets[i].getAttribute("name") == "skillqueue"){
skillrows = rowsets[i].getElementsByTagName("row");
}
}
//Defines Table Headers
$("#tableskillqueuelist").append(
"<thead>" +
"<tr>" +
"<th>Order: </th> "+
"<th>Skill Name: </th> "+
"<th>Training to: </th> "+
"<th>Starts:</th> "+
"<th>Ends:</th> "+
"</tr> "+
"</thead>"+
"<tbody>"
);
for(var i = 0; i < skillrows.length; i++){
(function(i, skillrows) {
$.get("../getitemname", {itemid:skillrows.getAttribute("typeID")},function(itemname){
$("#tableskillqueuelist").append(
"<tr> " +
"<td>" + skillrows.getAttribute("queuePosition") + ". " +
"<td>" + itemname + "</td>" +
"<td>" + "|Train to: " + skillrows.getAttribute("level") + "</td>" +
"<td>" + "|Training Starts: " + skillrows.getAttribute("startTime") + "</td>" +
"<td>" + "|Training Ends: " + skillrows.getAttribute("endTime") + "<td>" +
"</tr>"
);
})
})(i, skillrows[i]);
}
//Ends the table body
$("#tableskillqueuelist").append("</tbody>");
});
});
$(文档).ready(函数(){
*Lotsa更多代码*
$.get(“../skillqueue”,{keyid:keyid,charid:charid},函数(xmlskillqueue){
log(“XMLSkillQueue”);
log(xmlskillqueue);
//变量
var rowsets=xmlskillqueue.getElementsByTagName(“行集”);
var skillrows;
对于(var i=0;i
现在我想知道我需要做什么才能让它成功运行$(“#tableskillqueuelist”).tablesorter();方法。因为每次我尝试运行它时,#tableskillqueuelist似乎都是空的。您需要告诉table sorter您已经更改了数据,并且希望通过触发事件对其进行排序 文档中的示例: 嗯
$("table").tablesorter();
$("#ajax-append").click(function() {
$.get("assets/ajax-content.html", function(html) {
// append the "ajax'd" data to the table body
$("table tbody").append(html);
// let the plugin know that we made a update
$("table").trigger("update");
// set sorting column and direction, this will sort on the first and third column
var sorting = [[2,1],[0,0]];
// sort on the first column
$("table").trigger("sorton",[sorting]);
});
return false;
});