Javascript 删除数组中的同一对象
我正在搜索以删除存储在数组中的重复对象。此对象以JSON格式发送。这是它的结构:Javascript 删除数组中的同一对象,javascript,arrays,object,duplicates,Javascript,Arrays,Object,Duplicates,我正在搜索以删除存储在数组中的重复对象。此对象以JSON格式发送。这是它的结构: { "name":"root", "children":[ { "name":"name1", "children":[ { "name":"name1", "level":1 } ] }, { "name":"name1", "
{
"name":"root",
"children":[
{
"name":"name1",
"children":[
{
"name":"name1",
"level":1
}
]
},
{
"name":"name1",
"children":[
{
"name":"name1",
"level":1
}
]
},
{
"name":"name2",
"children":[
{
"name":"name2",
"level":3
}
]
}
]
}
在这种情况下,第一个或第二个名为name1的对象应该被删除,因为它们完全相同
这是我用来删除副本的算法,但它删除了我数组中的所有对象
for (var z in player.children){
var nameObject = playerchildren[z].name;
//console.log(nameObject);
for (var q in player.children){
//console.log(player.children[q].name);
if (nameObject == player.children[q].name){
console.log(nameObject + " = " + myBubble.children[q].name);
// delete player.children[z]; // Delete all ...
} else {
console.log(nameObject + " != " + player.children[q].name);
}
}
}
return player;
感谢您的帮助。在嵌套循环中,您应该跳过当前对象:
for (var z in player.children){
var nameObject = playerchildren[z].name;
//console.log(nameObject);
for (var q in player.children){
//console.log(player.children[q].name);
if (nameObject == player.children[q].name){
// this is true if z == q. that's why all objects get deleted
for (var z in player.children){
var nameObject = playerchildren[z].name;
//console.log(nameObject);
for (var q in player.children){
//console.log(player.children[q].name);
if ( q !== z && nameObject == player.children[q].name){
// now this should be better
在嵌套循环中,应跳过当前对象:
for (var z in player.children){
var nameObject = playerchildren[z].name;
//console.log(nameObject);
for (var q in player.children){
//console.log(player.children[q].name);
if (nameObject == player.children[q].name){
// this is true if z == q. that's why all objects get deleted
for (var z in player.children){
var nameObject = playerchildren[z].name;
//console.log(nameObject);
for (var q in player.children){
//console.log(player.children[q].name);
if ( q !== z && nameObject == player.children[q].name){
// now this should be better
首先,如果您的算法删除所有对象,这是正常的,因为您的循环首先测试当前对象
请参阅此链接以解决您的问题:首先,如果您的算法删除所有对象,这是正常的,因为您的循环首先测试当前对象
请参阅此链接以解决您的问题:好,谢谢,它可以正常工作,但我现在已删除对象的空值。是否可以删除循环中的空值?这可能会有所帮助:这是另一个主题。请尝试找到答案,如果没有,请问另一个问题好的,谢谢,它可以工作,但我现在有空值的对象删除。是否可以删除循环中的空值?这可能会有所帮助:这是另一个主题。请尝试找到答案,如果没有,请再问一个问题