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Javascript 如何在Ajax Get请求中获得HTML响应?_Javascript - Fatal编程技术网

Javascript 如何在Ajax Get请求中获得HTML响应?

Javascript 如何在Ajax Get请求中获得HTML响应?,javascript,Javascript,您可以使用此脚本获得html响应 $().ready(函数(){ $.ajax({ 键入:“获取”, 网址:'http://vindhyatest.comule.com/content.php', 跨域:是的, 成功:功能(数据){ $('#content').html(数据); }, 错误:函数(xhr、ajaxOptions、thrownError){ log('xHR:'+xHR); log('ajaxOption:'+ajaxOptions); log('thrownError:'+t

您可以使用此脚本获得html响应

$().ready(函数(){
$.ajax({
键入:“获取”,
网址:'http://vindhyatest.comule.com/content.php',
跨域:是的,
成功:功能(数据){
$('#content').html(数据);
},
错误:函数(xhr、ajaxOptions、thrownError){
log('xHR:'+xHR);
log('ajaxOption:'+ajaxOptions);
log('thrownError:'+thrownError);
}
});
});

详细说明您面临的问题
$.ajax({
        type: "GET",
        url: url,
        dataType: 'html',
        async: false,
        crossDomain: true,
        headers: {
            'Access-Control-Allow-Origin': '*',
            'Access-Control-Allow-Methods': 'GET, POST,PUT',
            'Content-Type': 'text/html'
        },
        success: function (data) {
            debugger;
            console.log($(data));
        },
        error: function (xhr, ajaxOptions, thrownError) {
            debugger;
            console.log('xHR: ' + xhr);
            console.log('ajaxOption: ' + ajaxOptions);
            console.log('thrownError: ' + thrownError);
        }
    });