Javascript 前端开发Mithril.js

如何使用mithil.js将二维数组的元素呈现到数据表中

对于表：

var dataSet = [
    [ "Tiger Nixon", "System Architect", "Edinburgh", "5421", "2011/04/25", "$320,800" ],
    [ "Garrett Winters", "Accountant", "Tokyo", "8422", "2011/07/25", "$170,750" ],
    [ "Ashton Cox", "Junior Technical Author", "San Francisco", "1562", "2009/01/12", "$86,000" ],
    [ "Cedric Kelly", "Senior Javascript Developer", "Edinburgh", "6224", "2012/03/29", "$433,060" ],
    [ "Airi Satou", "Accountant", "Tokyo", "5407", "2008/11/28", "$162,700" ],
    [ "Brielle Williamson", "Integration Specialist", "New York", "4804", "2012/12/02", "$372,000" ],
    [ "Herrod Chandler", "Sales Assistant", "San Francisco", "9608", "2012/08/06", "$137,500" ],
    [ "Rhona Davidson", "Integration Specialist", "Tokyo", "6200", "2010/10/14", "$327,900" ],
    [ "Colleen Hurst", "Javascript Developer", "San Francisco", "2360", "2009/09/15", "$205,500" ],
    [ "Sonya Frost", "Software Engineer", "Edinburgh", "1667", "2008/12/13", "$103,600" ],
    [ "Jena Gaines", "Office Manager", "London", "3814", "2008/12/19", "$90,560" ],
    [ "Quinn Flynn", "Support Lead", "Edinburgh", "9497", "2013/03/03", "$342,000" ],
    [ "Charde Marshall", "Regional Director", "San Francisco", "6741", "2008/10/16", "$470,600" ],
    [ "Haley Kennedy", "Senior Marketing Designer", "London", "3597", "2012/12/18", "$313,500" ],
    [ "Tatyana Fitzpatrick", "Regional Director", "London", "1965", "2010/03/17", "$385,750" ],
    [ "Michael Silva", "Marketing Designer", "London", "1581", "2012/11/27", "$198,500" ],
    [ "Paul Byrd", "Chief Financial Officer (CFO)", "New York", "3059", "2010/06/09", "$725,000" ],
    [ "Gloria Little", "Systems Administrator", "New York", "1721", "2009/04/10", "$237,500" ],
    [ "Bradley Greer", "Software Engineer", "London", "2558", "2012/10/13", "$132,000" ],
    [ "Dai Rios", "Personnel Lead", "Edinburgh", "2290", "2012/09/26", "$217,500" ],
    [ "Jenette Caldwell", "Development Lead", "New York", "1937", "2011/09/03", "$345,000" ],
    [ "Yuri Berry", "Chief Marketing Officer (CMO)", "New York", "6154", "2009/06/25", "$675,000" ],
    [ "Caesar Vance", "Pre-Sales Support", "New York", "8330", "2011/12/12", "$106,450" ],
    [ "Doris Wilder", "Sales Assistant", "Sidney", "3023", "2010/09/20", "$85,600" ],
    [ "Angelica Ramos", "Chief Executive Officer (CEO)", "London", "5797", "2009/10/09", "$1,200,000" ],
    [ "Gavin Joyce", "Developer", "Edinburgh", "8822", "2010/12/22", "$92,575" ],
    [ "Jennifer Chang", "Regional Director", "Singapore", "9239", "2010/11/14", "$357,650" ],
    [ "Brenden Wagner", "Software Engineer", "San Francisco", "1314", "2011/06/07", "$206,850" ],
    [ "Fiona Green", "Chief Operating Officer (COO)", "San Francisco", "2947", "2010/03/11", "$850,000" ],
    [ "Shou Itou", "Regional Marketing", "Tokyo", "8899", "2011/08/14", "$163,000" ],
    [ "Michelle House", "Integration Specialist", "Sidney", "2769", "2011/06/02", "$95,400" ],
    [ "Suki Burks", "Developer", "London", "6832", "2009/10/22", "$114,500" ],
    [ "Prescott Bartlett", "Technical Author", "London", "3606", "2011/05/07", "$145,000" ],
    [ "Gavin Cortez", "Team Leader", "San Francisco", "2860", "2008/10/26", "$235,500" ],
    [ "Martena Mccray", "Post-Sales support", "Edinburgh", "8240", "2011/03/09", "$324,050" ],
    [ "Unity Butler", "Marketing Designer", "San Francisco", "5384", "2009/12/09", "$85,675" ]
];

我的代码是：

function view_table(){
    var result="<table>";
    for(var i=start-1;i<start+outof-1;++i)
    {
        result+="<tr>";
        result+="<td>"+(i+1)+"</td>";
        for(var j=0;j<dataSet[i].length;++j)
        {
            result+="<td>"+dataSet[i][j]+"</td>";
        }
        result+="</tr>";
    }
    result+="</table>";
    return result
}

函数视图_表（）{
var结果=”；
对于（var i=start-1；i我发现了实现这一点的方法..其代码如下

function view_table(){
    var rows=[]
    var col=[]
    col.push(m("td","name"))
    col.push(m("td","designation"))
    col.push(m("td","location"))
    col.push(m("td","id no."))
    col.push(m("td","date of joining"))
    col.push(m("td","salary"))
    rows.push(m("tr",{style:"font-size:150%;background-color:orange;color:white;font-weight:bold"},col))
    for(var i=start-1;i<start+outof-1;++i)
    {
        for(var cols=[],j=0;j<dataSet[i].length;++j)
        {
            cols.push(m("td",{style:"font-size:120%;font-weight:bold;color:orange"}, dataSet[i][j]))
        }
        rows.push(m("tr", cols))
    }
    return m("table",{style:"border:1px solid orange;text-align:center;width:100%;"}, m("tbody", rows))
}

函数视图_表（）{
变量行=[]
var col=[]
col.push（m（“td”、“名称”））
柱推（m（“td”、“名称”））
柱推（m（“td”、“位置”））
col.push（m（“td”，“id号”）
col.push（m（“td”，“加入日期”））
上校推（m（“td”、“工资”））
push（m（“tr”，“style:”字体大小：150%；背景色：橙色；颜色：白色；字体大小：粗体“}，col））
对于（var i=start-1；i我发现了实现这一点的方法..其代码如下

function view_table(){
    var rows=[]
    var col=[]
    col.push(m("td","name"))
    col.push(m("td","designation"))
    col.push(m("td","location"))
    col.push(m("td","id no."))
    col.push(m("td","date of joining"))
    col.push(m("td","salary"))
    rows.push(m("tr",{style:"font-size:150%;background-color:orange;color:white;font-weight:bold"},col))
    for(var i=start-1;i<start+outof-1;++i)
    {
        for(var cols=[],j=0;j<dataSet[i].length;++j)
        {
            cols.push(m("td",{style:"font-size:120%;font-weight:bold;color:orange"}, dataSet[i][j]))
        }
        rows.push(m("tr", cols))
    }
    return m("table",{style:"border:1px solid orange;text-align:center;width:100%;"}, m("tbody", rows))
}

函数视图_表（）{
变量行=[]
var col=[]
col.push（m（“td”、“名称”））
柱推（m（“td”、“名称”））
柱推（m（“td”、“位置”））
col.push（m（“td”，“id号”）
col.push（m（“td”，“加入日期”））
上校推（m（“td”、“工资”））
push（m（“tr”，“style:”字体大小：150%；背景色：橙色；颜色：白色；字体大小：粗体“}，col））
对于（var i=start-1；i我知道您已经回答了自己的问题，但这里有一种不同的方法

m.mount(document.body, {
    view() {
        return m("table",
            m("thead",
                m("tr",
                    m("th", "Name"),
                    m("th", "Designation"),
                    m("th", "Location"),
                    m("th", "ID #"),
                    m("th", "Join Date"),
                    m("th", "Salary"),
                )
            ),

            m("tbody",
                dataSet.map((row) => m("tr",
                    row.map((cell) => m("td", cell))
                ))
            )
        );
    }
});

我还整理了一个。
我知道您已经回答了自己的问题，但这里有一种不同的方法

m.mount(document.body, {
    view() {
        return m("table",
            m("thead",
                m("tr",
                    m("th", "Name"),
                    m("th", "Designation"),
                    m("th", "Location"),
                    m("th", "ID #"),
                    m("th", "Join Date"),
                    m("th", "Salary"),
                )
            ),

            m("tbody",
                dataSet.map((row) => m("tr",
                    row.map((cell) => m("td", cell))
                ))
            )
        );
    }
});

我还提出了一个问题。
您是否只在jquery这样的库中使用javascript？是否只在jquery这样的库中使用javascript框架mithil.js？只有javascript框架mithil.json行51:9逗号才能在不支持现代ecmascript的旧浏览器中渲染，这完全是一个错误lid必须有这样的悬空逗号。我每天都使用qutebrowser。谷歌Chrome来测试你的小提琴。直到我删除了第51:9行的逗号，才可以在不支持现代ecmascript的旧浏览器中进行渲染。使用这样的悬空逗号是完全有效的。我使用qutebrowser进行da今天是。谷歌Chrome来测试你的小提琴。直到我删除了逗号，@Tivac的答案才呈现出来。剩下的就是添加样式。使用高阶数组函数比解决方案中使用的循环更有效@Tivac的答案更易于管理。剩下的就是添加样式s、 使用高阶数组函数比解决方案中使用的循环更有效