Javascript jQuery在每个$范围内突破$

Javascript jQuery在每个$范围内突破$,javascript,jquery,break,Javascript,Jquery,Break,我需要迭代AJAX响应,并在满足条件时中断事件处理程序。我在使用此代码时遇到问题: $.each(response, function(i, v) { // create mapbox object var map = L.mapbox.map('map', v.map_embed_id, { zoomAnimation: false }); var polygonLayer = L.mapbox.featureLayer().loadURL(

我需要迭代AJAX响应,并在满足条件时中断事件处理程序。我在使用此代码时遇到问题:

$.each(response, function(i, v) {

    // create mapbox object
    var map = L.mapbox.map('map', v.map_embed_id, {
        zoomAnimation: false
    });

    var polygonLayer = L.mapbox.featureLayer().loadURL('https://a.tiles.mapbox.com/v4/' + v.map_embed_id + '/features.json?access_token=abcde').addTo(map);

    polygonLayer.on('ready', function() {
        var layer = leafletPip.pointInLayer(latlng, polygonLayer, true);

        if (layer.length) {
            // this is where I need to break out of $.on 
            // and the current $.each iteration
        }
    });
});

我知道返回false会在每次迭代中突破$。但这更困难,因为我需要在事件处理程序中突破$。我能做什么?我可以使用触发器吗?

多亏@Kevin B建议使用递归,这就是我修复代码的方法

getMapsList().done(function(maps) {
    getMapboxMap(maps, geocode);
});

function getMapboxMap(maps, geocode) {

    var map_params   = maps[0];
    var map_embed_id = map_params.map_embed_id;

    if (maps.length > 0)
        maps.shift();

    // create mapbox object
    var map = L.mapbox.map('map', map_embed_id, {
        zoomAnimation: false
    });

    // create marker of address entered
    L.mapbox.featureLayer({
        type: 'Feature',
        geometry: {
            type: 'Point',
            coordinates: [
                geocode.location.lng,
                geocode.location.lat
            ]
        },
        properties: {
            title: address,
            'marker-size': 'medium',
            'marker-color': '#f44',
            'marker-symbol': 'star'
        }
    }).addTo(map);

    // create polygon layer and add to map from map's geojson
    var polygonLayer = L.mapbox.featureLayer().loadURL('https://a.tiles.mapbox.com/v4/' + map_embed_id + '/features.json?access_token=pk.eyJ1IjoiZW5nbGVzaWRldGVycml0b3JpZXMiLCJhIjoiekFIU0NlayJ9.rE9XdicgXc9aIiXJ9yn68w').addTo(map);

    // after polygon layer has been added to map
    polygonLayer.on('ready', function() {

        // featureLayer.getBounds() returns the corners of the furthest-out markers,
        // and map.fitBounds() makes sure that the map contains these.
        map.fitBounds(polygonLayer.getBounds());

        // create a latLng object based on lat/lng of address entered
        var latlng = L.latLng(geocode.location.lat, geocode.location.lng);

        // create point in layer object
        var layer = leafletPip.pointInLayer(latlng, polygonLayer, true);

        if (layer.length) {
            // found it
            return false;
        } else {
            if (maps.length > 0) {
                getMapboxMap(maps, geocode);
            }
        }
    });
}

function getMapsList() {
    return $.get('/utility/territories/maps-list');
}

是否确实需要为每个迭代的每个迭代绑定事件?这看起来有点可疑,可能就是我要解决的问题。可以用于事件处理程序并为每个事件返回false为什么要绑定就绪事件?你认为它能做什么?在这些事件被触发之前,每一个都会被完成。这里错的太多了。确保你发布了一个答案,展示了什么对未来的访问者有帮助