Javascript 我制作了一个jquery幻灯片,但它没有';如果我不能正常工作,我该怎么办
好吧,我从youtube上的一个视频系列中制作了这个jquery滑块,但它似乎工作不正常。。。图像最初会淡入,但随后下一个图像不会进入。我怎样才能解决这个问题。。由于不推荐使用的函数,我正在使用较旧版本的jquery 这是htmlJavascript 我制作了一个jquery幻灯片,但它没有';如果我不能正常工作,我该怎么办,javascript,jquery,html,css,Javascript,Jquery,Html,Css,好吧,我从youtube上的一个视频系列中制作了这个jquery滑块,但它似乎工作不正常。。。图像最初会淡入,但随后下一个图像不会进入。我怎样才能解决这个问题。。由于不推荐使用的函数,我正在使用较旧版本的jquery 这是html <!DOCTYPE html> <html> <head> <title> Home </title> <link rel
<!DOCTYPE html>
<html>
<head>
<title>
Home
</title>
<link rel="stylesheet" type="text/css" href="style.css">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js" type="text/javascript"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.min.js" type="text/javascript">
</script>
<script src="jquery-ui-1.8.18.js" type="text/javascript">
</script>
<script src="script.js" type="text/javascript">
</script>
</head>
<body class="body" onload="Slider()">
<div class="container">
<div class="bg">
<div class="mainHeader">
<nav>
<ul>
<li class="last">
<a href="#">Contact</a>
</li>
<li>
<a href="#">Products</a>
</li>
<li>
<a href="#">About</a>
</li>
<li>
<a href="#" class="active">Home</a>
</li>
</ul>
</nav>
</div>
<div class="topArea">
<div class="topAInfo">
<h2>
Here is just a simple title
</h2>
<p>
This is just a little bit of dummy text. This is just a little bit of dummy text. This is just a little bit of dummy text. This is just a little bit of dummy text.
</p>
</div>
</div>
<div class="middleArea">
<div class="slider">
<img id="1" src="slide1.jpg" border="0" alt="slide1" width="800px" height="350px">
<img id="2" src="slide2.jpg" border="0" alt="slide2" width="800px" height="350px">
<img id="3" src="slide3.jpg" border="0" alt="slide3" width="800px" height="350px">
</div>
<div class="middleAInfo">
<h3>
Welcome to
</h3>
<p>
A dummy website!!
</p>
</div>
<div class="latestNews">
<hr>
<h2>
Latest News
</h2>
<div class="post">
<p class="date">
March 28, 2015
</p>
<p>
New advanced update with double speed and a whole bunch of cool new st.. <a href="#">more>></a>
</p>
</div>
<div class="post">
<p class="date">
March 28, 2015
</p>
<p>
New advanced update with double speed and a whole bunch of cool new st.. <a href="#">more>></a>
</p>
</div>
<div class="newsLetter">
<div class="newsLInfo">
<h3>
Newsletter sign-up
</h3>
<hr>
<p>
If you would like to sign up for our free NewsLetter please enter your email below
</p><a href="#">Unsubscribe</a>
</div><input type="text" name="textBox" class="textBox" style="width:200px; height:20px;">
<div class="button1">
Submit
</div>
</div>
</div>
</div>
</div>
</div>
</body>
</html>
javascript:
function Slider(){
$(".slider #1").show("fade", 500);
$(".slider #1").delay(5500).hide("slide", {direction:'left'}, 500);
var sc = $(".slider img").size();
var count = 2;
setInterval(function(){
$("slider #"+count).show("slide", {direction:'right'}, 500);
$("slider #"+count).delay(5500).hide("slide", {direction:'left'}, 500);
if(count == sc){
count == 1;
}else{
count = count + 1;
}
},6500);
}
还有图像压缩
好吧,以下是使其无法工作的问题,您可以尝试一下:
count
的数据类型为int,这就是选择器找不到指向的DOM的原因。您应该像
count.toString()
那样编写代码$(“slider”+count)
,而$(“#”+count.toString())
是正确的方法您需要考虑的另一件事是如何向后滑动。问题在于语法错误,类选择器应该包含一个点 将
$(“滑块”)
更改为$(.slider”)
试试这个
function Slider(){
$(".slider #1").show("fade", 500);
$(".slider #1").delay(5500).hide("slide", {direction:'left'}, 500);
var sc = $(".slider img").size();
var count = 2;
setInterval(function(){
console.log(count);
$(".slider #" + count).show("slide", {direction:'right'}, 500);
$(".slider #" + count).delay(5500).hide("slide", {direction:'left'}, 500);
if(count == sc){
count == 1;
}else{
count = count + 1;
}
},6500);
}
并将滑块容器替换为
<div class="slider">
<img id="1" src="slide1.jpg" border="0" alt="slide1" width="800px" height="350px">
<img id="2" src="slide2.jpg" border="0" alt="slide2" width="800px" height="350px">
<img id="3" src="slide3.jpg" border="0" alt="slide3" width="800px" height="350px">
</div>
并确保将图像slider3.jpg重命名为slide3.jpg也许拼写检查器-“去擦亮”?“$(“#”+count.toString())是正确的方法“不必使用长格式的
count.toString()
(即使它有效)由于javascript中的字符串连接规则:count
如果附加到字符串,将转换为字符串。这个答案仍然包含错误“count==1”,这将不允许滑块前进/循环回到起点。
<div class="slider">
<img id="1" src="slide1.jpg" border="0" alt="slide1" width="800px" height="350px">
<img id="2" src="slide2.jpg" border="0" alt="slide2" width="800px" height="350px">
<img id="3" src="slide3.jpg" border="0" alt="slide3" width="800px" height="350px">
</div>