Javascript React:函数发送无限GET请求
组件,该组件从getConvForNum上的服务器获取数据,但不知何故它进入了一个无限循环。 即使我只保留render()和这个函数,它也会继续向服务器发送GET请求 OpentTickets.jsJavascript React:函数发送无限GET请求,javascript,reactjs,axios,Javascript,Reactjs,Axios,组件,该组件从getConvForNum上的服务器获取数据,但不知何故它进入了一个无限循环。 即使我只保留render()和这个函数,它也会继续向服务器发送GET请求 OpentTickets.js import React from 'react'; import axios from 'axios'; import {Button, Accordion, Card, Form} from 'react-bootstrap'; export default class PersonList
import React from 'react';
import axios from 'axios';
import {Button, Accordion, Card, Form} from 'react-bootstrap';
export default class PersonList extends React.Component {
state = {
people: [],
customer_pn: '',
date: '',
conversation: []
};
componentDidMount() {
axios.get(`/getongoing?limit=10`)
.then(res => {
const people = res.data;
this.setState({people});
});
}
getConvForNum(phone_nm) {
axios.get('/getconvfornum?customer_number=' + phone_nm.slice(1)).then(res => {
const conversation = res.data;
this.setState({conversation})
});
return (
this.state.conversation.map(message =>
<div>
<p>{message.from}</p>
<p>{message.body}</p>
</div>
)
)
}
render() {
return (
this.state.people.map(person =>
<>
<Accordion defaultActiveKey="0">
<Card>
<Card.Header>
<Accordion.Toggle as={Button} variant="button" eventKey="0">
Converstaion random
</Accordion.Toggle>
Phone number: {person}
</Card.Header>
<Accordion.Collapse eventKey="0">
<Card.Body>
{this.getConvForNum(person)}
<Form.Control type = 'text'/>
</Card.Body>
</Accordion.Collapse>
</Card>
</Accordion>
</>
)
)
}
}
从“React”导入React;
从“axios”导入axios;
从“react bootstrap”导入{按钮、手风琴、卡片、表格};
导出默认类PersonList扩展React.Component{
状态={
人员:[],
客户编号:'',
日期:'',
对话:[]
};
componentDidMount(){
axios.get(`/GetContinuous?limit=10`)
。然后(res=>{
const people=res.data;
这个.setState({people});
});
}
getConvForNum(电话号码){
get('/getconvfornum?customer_number='+phone_nm.slice(1))。然后(res=>{
const conversation=res.data;
this.setState({conversation})
});
返回(
this.state.conversation.map(消息=>
{message.from}
{message.body}
)
)
}
render(){
返回(
this.state.people.map(person=>
会话随机
电话号码:{person}
{this.getConvForNum(person)}
)
)
}
}
App.js
import {push as Menu} from 'react-burger-menu'
import React from "react";
import {BrowserRouter, Switch, Route, NavLink} from 'react-router-dom';
import Dashboard from "./Dashboard";
import AuthenticatedComponent from "./AuthenticatedComponent";
import Login from "./Login";
import OpenTickets from "./OpenTickets";
import ExportToLog from "./ExportToLog";
import LogOut from "./LogOut";
import '../css/slideBarNav.css';
import 'bootstrap/dist/css/bootstrap.min.css';
import '../css/style.css';
class App extends React.Component {
render() {
return (
<BrowserRouter>
<Switch>
<Route path="/login" component={Login}/>
<>
<Menu className='navBar'>
<NavLink exact to="/" className='menu-item' activeClassName='active'>Home</NavLink>
<NavLink to="/opentickets" className='menu-item' activeClassName='active'>Open Tickets</NavLink>
<NavLink to="/exportlog" className='menu-item' activeClassName='active'>Export Log</NavLink>
<NavLink to ='/logout' className='menu-item'>Log Out</NavLink>
</Menu>
<AuthenticatedComponent>
<Route path="/" exact component={Dashboard}/>
<Route path="/opentickets" component={OpenTickets}/>
<Route path="/exportlog" component={ExportToLog}/>
<Route path='/logout' component={LogOut}/>
</AuthenticatedComponent>
</>
</Switch>
</BrowserRouter>
);
}
}
export default App;
从“反应汉堡菜单”导入{push as Menu}
从“React”导入React;
从“react router dom”导入{BrowserRouter,Switch,Route,NavLink};
从“/Dashboard”导入仪表板;
从“/AuthenticatedComponent”导入AuthenticatedComponent;
从“/Login”导入登录名;
从“/OpenTickets”导入OpenTickets;
从“/ExportToLog”导入ExportToLog;
从“/LogOut”导入注销;
导入“../css/slideBarNav.css”;
导入'bootstrap/dist/css/bootstrap.min.css';
导入“../css/style.css”;
类应用程序扩展了React.Component{
render(){
返回(
家
公开票
导出日志
注销
);
}
}
导出默认应用程序;
不确定是什么导致了这个无限循环
我是react新手,所以我可能只是不理解渲染函数中的某些内容,您有一个
getConvForNum(person)
调用,它将执行get请求并设置状态,
SetState
将触发渲染函数调用,渲染将再次调用getConvForNum(person)
,依此类推
您可以在设置状态之前将this.state.conversation
与get调用返回的新值进行比较,以避免在此.setState({conversation})调用之前出现无限调用。您应该检查会话数组是否已更改