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Javascript 刷新或按下后退按钮id时提交表单,以响应用户的确认_Javascript_Jquery_Html_Form Submit_Page Refresh - Fatal编程技术网

Javascript 刷新或按下后退按钮id时提交表单,以响应用户的确认

Javascript 刷新或按下后退按钮id时提交表单,以响应用户的确认,javascript,jquery,html,form-submit,page-refresh,Javascript,Jquery,Html,Form Submit,Page Refresh,我正在开发一个测验模块。在测试页面中,当用户尝试刷新页面或尝试返回时,我应该提醒用户,如果他还想这样做,我应该提交表单。 这是我的HTML表单 <form method="post" name="form1" id="form1" action="testdone.php" > <?php $sql=mysql_query("SELECT * from test WHERE id='".$recordid."'"); $record = mysql_fetch_array($

我正在开发一个测验模块。在测试页面中,当用户尝试刷新页面或尝试返回时,我应该提醒用户,如果他还想这样做,我应该提交表单。
这是我的HTML表单

<form method="post" name="form1" id="form1" action="testdone.php" >
<?php 
$sql=mysql_query("SELECT * from test WHERE id='".$recordid."'");
$record = mysql_fetch_array($sql);
for($i=1;$i <= $record['noofquestion'];$i++)
{
        $sql1 = mysql_query("SELECT * FROM question WHERE id='".$questions[$i-1]."'");
        $ques= mysql_fetch_array($sql1);
        ?>
        <div class="col-xs-11 col-xs-offset-1">
        <?php echo "<p style=\"font-size:25px\">".$i.".".$ques['question']."</p><br>";?>
        <input type="radio" name="responce[<?php echo $i-1 ?>]" value="na" checked="checked" hidden="hidden">
        <input type="radio" name="responce[<?php echo $i-1 ?>]" value="a" required><font style="font-size:20px;" ><?php echo $ques['a']; ?></font>
        <input type="radio" name="responce[<?php echo $i-1 ?>]" value="b" required><font style="font-size:20px;"><?php echo $ques['b']; ?></font>
        <input type="radio" name="responce[<?php echo $i-1 ?>]" value="c" required><font style="font-size:20px;"><?php echo $ques['c']; ?></font>
        <input type="radio" name="responce[<?php echo $i-1 ?>]" value="d" required><font style="font-size:20px;"><?php echo $ques['d']; ?></font> 
        </div>
    <?php
       }
    ?><center><input class="btn btn-success" type="submit" value="SUBMIT" name="submitbutton" id="submitbutton"></center>
</form>


我看不到您提供的代码中有任何东西可以解释它为什么会提示用户。你是用jfiddle/codepen还是别的什么工具测试的?如果您正在发布到其他页面,这些站点可能会确认页面更改或刷新。@脚本中的window.onbeforeunload=function()将在页面重新加载时提示用户。当用户在提示符中选择离开页面时,我需要提交表单,但它只是刷新表单。
<script>
    window.onbeforeunload = function() {
    $('#form1').submit();
    return true;
  };
</script>
 function CountDown(duration, display) {
        if (!isNaN(duration)) {
            var timer = duration, minutes, seconds;

          var interVal=  setInterval(function () {
                minutes = parseInt(timer / 60, 10);
                seconds = parseInt(timer % 60, 10);

                minutes = minutes < 10 ? "0" + minutes : minutes;
                seconds = seconds < 10 ? "0" + seconds : seconds;

                $(display).html("<b style=\"font-size:25px;\">Time left: " + minutes + "m : " + seconds + "s" + "</b>");
                if (--timer < 0) {
                    timer = duration;
                   SubmitFunction();
                   $('#display').empty();
                  clearInterval(interVal)
                }

                },1000);
        }
    }

    function SubmitFunction(){
        document.form1.submit(); 
        return false;
    }
CountDown(<?php echo $duration*60; ?>,$('#display'));