Javascript 从选择器访问道具'；s结果函数

我有一个与文档中类似的用例，但是在我的例子中，

visibilityFilter

来自于道具。有没有一种方法可以实现下面这样的目标

export const getVisibleTodos = createSelector(
  getTodos,
  (todos, props) => {
    // props is undefined Props (or 
ownProps
) is the second argument passed to any 
mapStateToProps
 function.


Using that, you can extract the property you want as one of the inputs to your 
resultFunc
.


export const getVisibleTodos = createSelector(
  getTodos,
  (state, props) => props.visibilityFilter,
  (todos, visibilityFilter) => {
    switch (visibilityFilter) {
      case 'SHOW_ALL':
        return todos
      case 'SHOW_COMPLETED':
        return todos.filter(t => t.completed)
      case 'SHOW_ACTIVE':
        return todos.filter(t => !t.completed)
    }
  }
)

导出常量getVisibleTodos=createSelector(
盖托多斯，
（待办事项、道具）=>{
//道具未定义

使用它，您可以提取所需的属性作为
resultFunc
的输入之一


使用它，您可以提取所需的属性作为
resultFunc
的输入之一