Javascript 通过事件和循环等待两个承诺
我有一段代码如下:Javascript 通过事件和循环等待两个承诺,javascript,node.js,loops,events,child-process,Javascript,Node.js,Loops,Events,Child Process,我有一段代码如下: for(let j = 0; j < someNumber; j++) { const forkedChildOne = fork("./child.js"); const childOne = await new Promise((resolve, reject) => { forkedChildOne.on('message', (msg){ // someCode
for(let j = 0; j < someNumber; j++) {
const forkedChildOne = fork("./child.js");
const childOne = await new Promise((resolve, reject) => {
forkedChildOne.on('message', (msg){
// someCode
resolve(msg);
});
});
}
for(let i = 0; i < someAnotherNumber; i++) {
const forkedChildTwo = fork("./child_numberTwo.js");
const childTwo = await new Promise((resolve, reject) => {
forkedChildTwo.on('message', (msg){
// someCode
resolve(msg);
});
});
}
for(设j=0;j{
forkedChildOne.on('message',(msg){
//一些代码
解决(msg);
});
});
}
for(设i=0;i{
forkedChildTwo.on('message',(msg){
//一些代码
解决(msg);
});
});
}
但在这里,它首先等待第一个循环完成,然后进入第二个循环。但我需要同时运行它们。我该怎么做?谢谢。将它们放在用
async
关键字定义的单独函数中。然后依次调用这两个函数
const forkloop = async (number, js) {
for(let j = 0; j < number; j++) {
const forked = fork(js);
const child = await new Promise((resolve, reject) => {
forked.on('message', (msg){
// someCode
resolve(msg);
});
});
}
}
const init = async () => {
/* Do not await here */ forkloop(someNumber, './child.js');
/* Do not await here */ forkloop(someAnotherNumber, './child_numberTwo.js');
}
init();
const forkloop=async(数字,js){
for(设j=0;j{
forked.on('message',(msg){
//一些代码
解决(msg);
});
});
}
}
const init=async()=>{
/*不要在这里等待*/forkloop(someNumber,'./child.js');
/*不要在这里等待*/forkloop(someAnotherNumber'./child_numberTwo.js');
}
init();
您能尝试使用Promise.all吗?请尝试下面的代码。我还没有测试过它,但我相信它应该能工作
设arrayRequests=[
forkedChildOne.on('message'),
forkedChildTwo.on('message')
返回Promise.all(arrayRequests)。然后(results=>{
let resultForkedChildOne = results[0];
let resultForkedChildTwo = results[1];
}))
你不能同时运行两个循环,谢谢。成功了。