Javascript 插入到特定表中

Javascript 插入到特定表中,javascript,php,html,mysql,Javascript,Php,Html,Mysql,主PHP文件- <html> <head> <script type="text/javascript" src="MyJS.js"></script> <body> <?php include ("connection.php"); $result = mysqli_query($con, "SELECT * FROM stu_rec"); while($stu = mysqli_fetch_arra

主PHP文件-

<html>
<head>
<script type="text/javascript" src="MyJS.js"></script>
<body>
<?php
    include ("connection.php");

    $result = mysqli_query($con, "SELECT * FROM stu_rec");

    while($stu = mysqli_fetch_array($result)){
        echo "<h3>" . $stu["Name"] . "<h3>";
        echo "<h3>" . $stu["FirstName"] . "<h3>";
        echo "<h3>" . $stu["SID"] . "<h3>";
        echo "<h3>" . $stu["Email"] . "<h3>";
    }
?>

<form action="insert.php" method="post">
Name: <input type="text" name="Name">
First Name: <input type="text" name="FirstName">
SID: <input type="int" name="SID">
Email: <input type="text" name="Email">
<input type="submit">
</form>

<select>
    <option id="mon" value="1"></option>
    <option id="tue" value="2"></option>
    <option id="thu" value="3"></option>
    <option id="fri" value="4"></option>
</select>
<script>
remaining();
</script>
</body>
</head>
</html>
我有4个数据库表。从下拉菜单中选择星期一后,将插入到“表1”,从下拉菜单中选择星期二后,将插入到“表2”,依此类推。请告诉我怎么做。。。我在这方面很新。请欣赏我愚蠢的错误


谢谢。

将菜单放入表单中,以便提交其值:

<form action="insert.php" method="post">
Name: <input type="text" name="Name">
First Name: <input type="text" name="FirstName">
SID: <input type="int" name="SID">
Email: <input type="text" name="Email">
<select name="day">
    <option id="mon" value="1"></option>
    <option id="tue" value="2"></option>
    <option id="thu" value="3"></option>
    <option id="fri" value="4"></option>
</select>
<input type="submit">
</form>

将名称添加到“选择”:

<select name="my_select_name">

但是请注意,在将从用户检索到的数据插入数据库之前,您不会对其进行任何筛选,这是非常危险的,并且会导致错误/SQL注入

成功了!谢谢在我的基本工作完成后,我将进行验证!不过谢谢你的建议。。。你太棒了!:)
<form action="insert.php" method="post">
Name: <input type="text" name="Name">
First Name: <input type="text" name="FirstName">
SID: <input type="int" name="SID">
Email: <input type="text" name="Email">
<select name="day">
    <option id="mon" value="1"></option>
    <option id="tue" value="2"></option>
    <option id="thu" value="3"></option>
    <option id="fri" value="4"></option>
</select>
<input type="submit">
</form>
$table = "table" . $_POST['day'];
$sql="INSERT INTO $table (Name, FirstName, SID, Email)
    VALUES
    ('$_POST[Name]','$_POST[FirstName]','$_POST[SID]','$_POST[Email]')";
<select name="my_select_name">
$sql="INSERT INTO table".$_POST['my_select_name']." (Name, FirstName, SID, Email)