Javascript for循环在Livescript中每次都指定相同的函数

我希望“x”的结果、“y”的结果和“z”的结果是一样的：

在Livescript中：

x = 
  a: -> 3 
  b: -> 4 

y = {}
for k, v of x 
  console.log "key: ", k, "val: ", v 
  y[k] = -> v.call this 


console.log "y is: ", y 
console.log "x's: ", x.a is x.b   # should return false, returns false
console.log "y's: ", y.a is y.b   # should return false, returns true

z = {}
z['a'] = -> 
  x.a.call this 

z['b'] = -> 
  x.b.call this 

console.log "z's: ", z.a is z.b  # should return false, returns false

x = 
  a: -> 3 
  b: -> 4 

y = {}
for k, v of x 
  console.log "key: ", k, "val: ", v 
  y[k] = ``function (){return v.call(this)}``


console.log "y is: ", y 
console.log "x's: ", x.a is x.b   # should return false, returns false
console.log "y's: ", y.a is y.b   # should return false, returns true

z = {}
z['a'] = -> 
  x.a.call this 

z['b'] = -> 
  x.b.call this 

console.log "z's: ", z.a is z.b  # should return false, returns false

在Javascript中：

var x, y, k, v, z;
x = {
  a: function(){
    return 3;
  },
  b: function(){
    return 4;
  }
};
y = {};
for (k in x) {
  v = x[k];
  console.log("key: ", k, "val: ", v);
  y[k] = function (){return v.call this};
}
console.log("y is: ", y);
console.log("x's: ", x.a === x.b);
console.log("y's: ", y.a === y.b);
z = {};
z['a'] = function(){
  return x.a.call(this);
};
z['b'] = function(){
  return x.b.call(this);
};
console.log("z's: ", z.a === z.b);

var x，y，k，v，z；
x={
a:函数（）{
返回3；
},
b:函数（）{
返回4；
}
};
y={}；
对于（k/x）{
v=x[k]；
控制台日志（“键：，k，“val:，v”）；
y[k]=fn$；
}
log（“y是：，y”）；
log（“x's:，x.a==x.b”）；
log（“y's:，y.a==y.b”）；
z={}；
z['a']=函数（）{
返回x.a.呼叫（此）；
};
z['b']=函数（）{
返回x.b.呼叫（此）；
};
log（“z's:，z.a==z.b”）；
函数fn$（）{
返回v.呼叫（本）；
}

问题的根源是Livescript的

fn$

优化。以下代码运行良好：

现场脚本：

x = 
  a: -> 3 
  b: -> 4 

y = {}
for k, v of x 
  console.log "key: ", k, "val: ", v 
  y[k] = -> v.call this 


console.log "y is: ", y 
console.log "x's: ", x.a is x.b   # should return false, returns false
console.log "y's: ", y.a is y.b   # should return false, returns true

z = {}
z['a'] = -> 
  x.a.call this 

z['b'] = -> 
  x.b.call this 

console.log "z's: ", z.a is z.b  # should return false, returns false

x = 
  a: -> 3 
  b: -> 4 

y = {}
for k, v of x 
  console.log "key: ", k, "val: ", v 
  y[k] = ``function (){return v.call(this)}``


console.log "y is: ", y 
console.log "x's: ", x.a is x.b   # should return false, returns false
console.log "y's: ", y.a is y.b   # should return false, returns true

z = {}
z['a'] = -> 
  x.a.call this 

z['b'] = -> 
  x.b.call this 

console.log "z's: ", z.a is z.b  # should return false, returns false

Javascript:

var x, y, k, v, z;
x = {
  a: function(){
    return 3;
  },
  b: function(){
    return 4;
  }
};
y = {};
for (k in x) {
  v = x[k];
  console.log("key: ", k, "val: ", v);
  y[k] = function (){return v.call this};
}
console.log("y is: ", y);
console.log("x's: ", x.a === x.b);
console.log("y's: ", y.a === y.b);
z = {};
z['a'] = function(){
  return x.a.call(this);
};
z['b'] = function(){
  return x.b.call(this);
};
console.log("z's: ", z.a === z.b);

---

我不相信公认的自我回答。

v

参考仍在更改

您想要的是let的

：

y = {}
for let k, v of x 
  console.log "key: ", k, "val: ", v 
  y[k] = -> v.call this 

您将
fn$
分配给
y
的所有属性，那么为什么
y.a
和
y.b
应该不同呢？你希望它们包含什么？如果你检查你的控制台，你会看到
y
是一个带有
a:function fn$（）
和
b:function fn$（）
的对象，所以比较结果返回真值。我在发布问题后立即注意到
fn$
优化。非常感谢。