Javascript 将错误获取为未捕获的SyntaxError:意外标识符

我试图通过ajax发布数据，但下面的错误是我的代码

jQuery.ajax({
                    url : '',                           
                    type: 'POST',                                           
                    data : {oid:1934,ConsigneeAddress1:85/18 BDD
CHAWL,ConsigneeAddress2:D N WAKARIKAR
MARG,ConsigneeMobile:097731454620,ConsigneeName:V
Boga,ConsigneePincode:400018,CommodityDetail1:SOVA Draksh & Bitter
Orange
..,CreditReferenceNo:1934,InvoiceNo:1934,PickupDate:2018-03-29,SubProductCode:C},
                    success: function(data)
                    {               
                        alert(data);
                    },
                    error: function (jqXHR, textStatus, errorThrown)
                    {

                    }
                });

---

请使用以下命令，并将字符串值用引号括起来。读-

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暗示这是无效的js

1:85/18 BDD CHAWL

生成

data

属性的代码显然充满了语法错误，当然它不会运行。解决方案是修复语法错误。第一个是从

1:85/18 BDD中的
B
开始。投票结束，因为输入错误/不重复/将来没有用。
jQuery.ajax({
  url: "",
  type: "POST",
  data: {
    oid: "1934",
    ConsigneeAddress1: "85/18 BDD CHAWL",
    ConsigneeAddress2: "D N WAKARIKAR MARG",
    ConsigneeMobile: "097731454620",
    ConsigneeName: "V Boga",
    ConsigneePincode: "400018",
    CommodityDetail1: "SOVA Draksh & Bitter Orange..",
    CreditReferenceNo: "1934",
    InvoiceNo: "1934",
    PickupDate: "2018-03-29",
    SubProductCode: "C"
  },
  success: function(data) {
    alert(data);
  },
  error: function(jqXHR, textStatus, errorThrown) {}
});