如何在javascript中获取一个负责URL的长度

我需要

JSONOBJECT.routingpath.coordinates.length的长度
我得到了这个url的响应


来自服务器的响应

[{
    "idtaxiroute": "3",
    "routingpath": {
        "type": "LineString",
        "coordinates": [
            [49.9670749, 7.8994591],
            [49.9682897, 7.898872900000001],
            [49.9682897, 7.898872900000001],
            [49.9680662, 7.897596899999999],
            [49.9680662, 7.897596899999999],
            [49.9689168, 7.897404499999999],
            [49.9689168, 7.897404499999999],
            [49.9690376, 7.895451],
            [49.9690376, 7.895451],
            [49.9688003, 7.891565000000001],
            [49.9688003, 7.891565000000001],
            [49.966386, 7.888530899999999],
            [49.966386, 7.888530899999999],
            [49.9651325, 7.8884534],
            [49.9651325, 7.8884534],
            [49.9411728, 7.912222499999999],
            [49.9411728, 7.912222499999999],
            [49.9391022, 7.9152532],
            [49.9391022, 7.9152532],
            [49.9337381, 7.9157891],
            [49.9337381, 7.9157891],
            [49.9241653, 7.829844099999999],
            [49.9241653, 7.829844099999999],
            [49.9259564, 7.8275102],
            [49.9259564, 7.8275102],
            [49.922877, 7.8259417],
            [49.922877, 7.8259417],
            [49.92355939999999, 7.8055037],
            [49.92355939999999, 7.8055037],
            [49.9258713, 7.8004553],
            [49.9258713, 7.8004553],
            [49.9262293, 7.7978919],
            [49.9262293, 7.7978919],
            [49.92596469999999, 7.795387600000001],
            [49.92596469999999, 7.795387600000001],
            [49.9216437, 7.7577913],
            [49.9216437, 7.7577913],
            [49.91755209999999, 7.7473702],
            [49.91755209999999, 7.7473702],
            [49.9107566, 7.726173299999999],
            [49.9107566, 7.726173299999999],
            [49.9115306, 7.725327200000001]
        ]
    },
    "taxiid": 551,
    "riderequestid": 7
}, {
    "idtaxiroute": "4",
    "routingpath": {
        "type": "LineString",
        "coordinates": [
            [49.9670749, 7.8994591],
            [49.9670378, 7.899477099999999],
            [49.9670378, 7.899477099999999],
            [49.9651449, 7.898171800000001],
            [49.9651449, 7.898171800000001],
            [49.9645179, 7.894035400000001],
            [49.9645179, 7.894035400000001],
            [49.9605222, 7.893961699999999],
            [49.9605222, 7.893961699999999],
            [49.95326799999999, 7.902490999999999],
            [49.95326799999999, 7.902490999999999],
            [49.9518747, 7.9065943],
            [49.9518747, 7.9065943],
            [49.9495675, 7.907795699999999],
            [49.9495675, 7.907795699999999],
            [49.9479066, 7.9125997],
            [49.9479066, 7.9125997],
            [49.9405005, 7.910934200000001],
            [49.9405005, 7.910934200000001],
            [49.9400513, 7.9114172]
        ]
    },
    "taxiid": 551,
    "riderequestid": 7
}]

代码：

for（var i=0；i

你能帮我吗？
在计算使用
i
的
循环的
极限时，使用
JSONOBJECT[i]
是没有意义的

您需要嵌套循环，一个用于
JSONOBJECT
数组，一个用于
坐标
的内部循环

for (var i = 0; i < JSONOBJECT.length; i++) {
    var coords = JSONOBJECT[i].routingpath.coordinates;
    for (var j = 0; j < coords.length; j++) {
        console.log("Type: " + coords[j]);
    }
}

for（var i=0；i
您的确切要求是什么…？我想要一个带坐标的循环，并在openlayers中绘制一条多段线，为此，我需要坐标的长度来确定循环的长度
for (var i = 0; i < JSONOBJECT.length; i++) {
    var coords = JSONOBJECT[i].routingpath.coordinates;
    for (var j = 0; j < coords.length; j++) {
        console.log("Type: " + coords[j]);
    }
}