Javascript正则表达式模式将多个字符串（AND、OR）与单个字符串匹配
我需要根据一个相当复杂的查询筛选字符串集合-在其“原始”形式中，它如下所示：Javascript正则表达式模式将多个字符串（AND、OR）与单个字符串匹配,javascript,regex,match,Javascript,Regex,Match,我需要根据一个相当复杂的查询筛选字符串集合-在其“原始”形式中，它如下所示： nano* AND (regulat* OR *toxic* OR ((risk OR hazard) AND (exposure OR release)) ) ^ # Anchor search to start of string (?=.*\bnano) # Assert that the string contains a word that starts with
nano* AND (regulat* OR *toxic* OR ((risk OR hazard) AND (exposure OR release)) )
^ # Anchor search to start of string
(?=.*\bnano) # Assert that the string contains a word that starts with nano
(?= # AND assert that the string contains...
(?: # either
.*\bregulat # a word starting with regulat
| # OR
.*toxic # any word containing toxic
| # OR
(?= # assert that the string contains
.* # any string
(?: # followed by
\brisk\b # the word risk
| # OR
\bhazard\b # the word hazard
) # (end of inner OR alternation)
) # (end of first AND condition)
(?= # AND assert that the string contains
.* # any string
(?: # followed by
\bexposure\b # the word exposure
| # OR
\brelease\b # the word release
) # (end of inner OR alternation)
) # (end of second AND condition)
) # (end of outer OR alternation)
) # (end of lookahead assertion)
Workshop on the Second Regulatory Review on Nanomaterials, 30 January 2013, Brussels
/(nano[a-zA-Z])?(regulat[a-zA-Z]|[a-zA-Z]toxic[a-zA-Z]|((risk|hazard)*(exposure|release)))/i
感谢所有帮助正则表达式必须按顺序在字符串中移动。模式中的“regulat”之前有“nano”，但它们在测试字符串中交换。我不使用正则表达式来完成这项工作，而是坚持使用普通的旧字符串解析：
if (str.indexOf('nano') > -1) {
if (str.indexOf('regulat') > -1 || str.indexOf('toxic') > -1
|| ((str.indexOf('risk') > - 1 || str.indexOf('hazard') > -1)
&& (str.indexOf('exposure') > -1 || str.indexOf('release') > -1)
)) {
/* all tests pass */
}
}
如果您想实际捕获单词（例如，从“regulat”所在的位置获取“regulator”，我会将句子按分词分隔并检查单个单词。单个正则表达式不是用于此的合适工具，IMO:
/^(?=.*\bnano)(?=(?:.*\bregulat|.*toxic|(?=.*(?:\brisk\b|\bhazard\b))(?=.*(?:\bexposure\b|\brelease\b))))/i.test(subject))
nano* AND (regulat* OR *toxic* OR ((risk OR hazard) AND (exposure OR release)) )
^ # Anchor search to start of string
(?=.*\bnano) # Assert that the string contains a word that starts with nano
(?= # AND assert that the string contains...
(?: # either
.*\bregulat # a word starting with regulat
| # OR
.*toxic # any word containing toxic
| # OR
(?= # assert that the string contains
.* # any string
(?: # followed by
\brisk\b # the word risk
| # OR
\bhazard\b # the word hazard
) # (end of inner OR alternation)
) # (end of first AND condition)
(?= # AND assert that the string contains
.* # any string
(?: # followed by
\bexposure\b # the word exposure
| # OR
\brelease\b # the word release
) # (end of inner OR alternation)
) # (end of second AND condition)
) # (end of outer OR alternation)
) # (end of lookahead assertion)
if (/\bnano/i.test(str) &&
(
/\bregulat|toxic/i.test(str) ||
(
/\b(?:risk|hazard)\b/i.test(str) &&
/\b(?:exposure|release)\b/i.test(str)
)
)
) /* all tests pass */
您可能想试试。在您的示例字符串中，“nano”位于“regulatory”之后，但在您的正则表达式中，情况正好相反。这其中是否有任何预期的模式，即一个总是位于另一个之前？再举几个示例将有助于解释您的要求。@Barney-好建议，我就是这样得到的far@Chirag64-我是matchi的弦ng最初是来自此提要的推文：-因此，没有顺序，我们只是试图减少数量并增加相关性。@QL Studio:在这种情况下，恐怕您必须使用多个if条件和and&或，而不是尝试将所有内容都放在一个正则表达式中。@EP-请参阅上面的注释，我输入的字符串的顺序我的匹配和它的内容一样随机。。我只是尝试根据正则表达式对大量推文进行“筛选”-也许这是错误的方法？@QLStudio我的建议不适合吗？@EP-是的，对不起-你的解决方案解决了顺序问题。。但我仍然可以使用通配符（*）正常JS搜索中的字符？我需要匹配nano*（如nanotechnology）和regulat*（如regulation）
indexOf“nanotechnology”。indexOf（'nano'）0-1“\b”/\b/新正则表达式（“\\b”）/\brisk\b/“风险”“存在风险！”“brisk”“风险”“