Javascript Sequelize查询从表中选择*只返回一行

我目前正在使用PostgreSQL和Sequelize.js查询一些数据。当我使用sequelize.query（）时，它只返回一行数据，但当我通过pgAdmin输入数据时，它会按预期工作

下面是我在sequelize.query（）中使用的代码

这是nodejs代码

const getRank = (option, logs = {}) => new Promise(async (resolve, reject) => {
  try {
    let { offset, limit } = option;
    if (!limit) limit = 10;
    const result = await sequelize.query(
      `SELECT table2.student_id,
              s.canvasser_name,
              l.level_name,
              table2.total_score
       FROM (SELECT table1.student_id,
                    sum(table1.max_score) total_score
             FROM (SELECT sq.student_id,
                   max(sq.score) max_score
                   FROM public.student_quiz sq
                   GROUP BY sq.quiz_id, sq.student_id) table1
             GROUP BY table1.student_id) table2
       INNER JOIN public.student s
               ON s.id = table2.student_id
       INNER JOIN public.level l
               ON l.id = s.level_id
       ORDER BY table2.total_score DESC
       LIMIT 10;`,
      { plain: true }
    );

    return resolve(result);
  } catch (error) {
    let customErr = error;
    if (!error.code) customErr = Helpers.customErrCode(error, null, undefinedError);
    logger.error(logs);
    return reject(customErr);
  }
});

下面是使用上述函数的代码

const getRankController = async (req, res) => {
  try {
    const { offset, limit } = req.query;
    const result = await getRank({ offset, limit });

    if (result.length < 1) {
      return Helpers.response(res, {
        success: false,
        message: 'cannot get score list'
      }, 404);
    }

    return Helpers.response(res, {
      success: true,
      result
    });
  } catch (error) {
    return Helpers.error(res, error);
  }
};

这一个不起作用，因为它是嵌套函数，我不知道如何复制它

我试着做一些简单的查询，比如SELECT*FROM table，它返回一行，然后我发现我需要在表名中添加“public”，这样它就变成了SELECT*FROM public.table，结果就成功了。在我尝试第二个代码块中的代码之前

---

任何回答或建议都将不胜感激，谢谢。

我想您需要指出一种查询类型，并删除如下

plain:true

选项：

const result = await sequelize.query(
      `SELECT table2.student_id,
              s.canvasser_name,
              l.level_name,
              table2.total_score
       FROM (SELECT table1.student_id,
                    sum(table1.max_score) total_score
             FROM (SELECT sq.student_id,
                   max(sq.score) max_score
                   FROM public.student_quiz sq
                   GROUP BY sq.quiz_id, sq.student_id) table1
             GROUP BY table1.student_id) table2
       INNER JOIN public.student s
               ON s.id = table2.student_id
       INNER JOIN public.level l
               ON l.id = s.level_id
       ORDER BY table2.total_score DESC
       LIMIT 10;`,
      { 
        type: Sequelize.QueryTypes.SELECT
      }
    );

从Sequelize文档：

options.plain - Sets the query type to SELECT and return a single row

---

似乎您的表位于

Public

schema中，因此它在您选择带有schema的表时起作用name@JimMacaulay我明白了，你知道为什么它只返回一行吗。我的意思是，如果它不返回任何值，我就会得到它，但为什么它只返回一个呢？也许问题出在sequelize代码中。把它添加到问题中是个好主意。@bjarniranarsson打得好，我已经更新了。请看一看。您是否尝试在

返回解析（结果）处设置断点然后看什么是
结果
内容？添加了它，这里仍然没有运气。伙计，你不会相信我一直在寻找这个答案。非常感谢你，你是最棒的。
const result = await sequelize.query(
      `SELECT table2.student_id,
              s.canvasser_name,
              l.level_name,
              table2.total_score
       FROM (SELECT table1.student_id,
                    sum(table1.max_score) total_score
             FROM (SELECT sq.student_id,
                   max(sq.score) max_score
                   FROM public.student_quiz sq
                   GROUP BY sq.quiz_id, sq.student_id) table1
             GROUP BY table1.student_id) table2
       INNER JOIN public.student s
               ON s.id = table2.student_id
       INNER JOIN public.level l
               ON l.id = s.level_id
       ORDER BY table2.total_score DESC
       LIMIT 10;`,
      { 
        type: Sequelize.QueryTypes.SELECT
      }
    );

options.plain - Sets the query type to SELECT and return a single row