Javascript 如何访问json字符串的属性
我的数据库表中有一个JSON字符串，但它的根元素名为空Javascript 如何访问json字符串的属性,javascript,jquery,asp.net,json,ajax,Javascript,Jquery,Asp.net,Json,Ajax,我的数据库表中有一个JSON字符串，但它的根元素名为空 {"": [ {"ID":18,"MenuName":"dsadasdasd","IsActive":"InActive"}, {"ID":17,"MenuName":"Karachi","IsActive":"Active"}, {"ID":2,"MenuName":"User Management","IsActive":"Active"}, {"ID":1,"MenuName":"Home","IsActive":"A
{"": [
{"ID":18,"MenuName":"dsadasdasd","IsActive":"InActive"},
{"ID":17,"MenuName":"Karachi","IsActive":"Active"},
{"ID":2,"MenuName":"User Management","IsActive":"Active"},
{"ID":1,"MenuName":"Home","IsActive":"Active"}
]}
function Get_DataTable() {
$.ajax({
url: "GridView_JqueryFunctionality.aspx/CallDataTable_EmptyRootName",
type: "POST",
data: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (data) {
alert(data.d) // showing json is fine
var MyData = $.parseJSON(data.d);
for (i = 0; i < Object.keys(MyData).length; i++) {
alert(MyData[i].ID + ' : ' + MyData[i].MenuName);
}
}
});
}
[WebMethod(true)]
public static string CallDataTable_EmptyRootName(){
List<Category> Categories = new List<Category>();
clsMenu objMenu = new clsMenu();
DataTable dt = new DataTable();
objMenu.GetAllMenu(dt);
if (dt.Rows.Count > 0){
string jsonString = ConversionExtension.DataTabelToJson(dt);
return jsonString.ToString();
}else{
return "";
}
}
[WebMethod（true）]
公共静态字符串CallDataTable_EmptyRootName（）{
列表类别=新列表（）；
clsMenu objMenu=新的clsMenu（）；
DataTable dt=新的DataTable（）；
objMenu.GetAllMenu（dt）；
如果（dt.Rows.Count>0）{
字符串jsonString=ConversionExtension.DataTabelToJson（dt）；
返回jsonString.ToString（）；
}否则{
返回“”；
}
}
它给了我
未定义的未定义的var a = {
"": [
{
"ID": 18,
"MenuName": "dsadasdasd",
"IsActive": "InActive"
},
{
"ID": 17,
"MenuName": "Karachi",
"IsActive": "Active"
},
{
"ID": 2,
"MenuName": "User Management",
"IsActive": "Active"
},
{
"ID": 1,
"MenuName": "Home",
"IsActive": "Active"
}
]
}
console.log(a[""]);
请尝试运行上面的代码。注意，尽管根名称为空，我们仍然可以访问objects元素。假设您的对象有一个变量名，您可以使用空字符串作为键引用它
var a = {
"": [
{
"ID": 18,
"MenuName": "dsadasdasd",
"IsActive": "InActive"
},
{
"ID": 17,
"MenuName": "Karachi",
"IsActive": "Active"
},
{
"ID": 2,
"MenuName": "User Management",
"IsActive": "Active"
},
{
"ID": 1,
"MenuName": "Home",
"IsActive": "Active"
}
]
}
console.log(a[""]);
请尝试运行上面的代码。注意，尽管根对象的名称为空，我们仍然可以访问objects元素。您必须使用括号访问根对象中的no name属性，然后遍历项数组
success: function(response) {
var data = $.parseJSON(response.d);
var list = data[""];
list.forEach(function(item, i) {
console.log(item);
console.log(item.ID, ' -> ', item.MenuName);
});
}
您必须使用括号访问根对象中的no-name属性，然后遍历项数组
success: function(response) {
var data = $.parseJSON(response.d);
var list = data[""];
list.forEach(function(item, i) {
console.log(item);
console.log(item.ID, ' -> ', item.MenuName);
});
}
function Get_DataTable() {
$.ajax({
url: "GridView_JqueryFunctionality.aspx/CallDataTable_EmptyRootName",
type: "POST",
data: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (data) {
alert(data.d) // showing json is fine
var MyData = $.parseJSON(data.d)[""];
for (i = 0; i < MyData.length; i++) {
alert(MyData[i].ID + ' : ' + MyData[i].MenuName);
}
}
});
}
function Get_DataTable() {
$.ajax({
url: "GridView_JqueryFunctionality.aspx/CallDataTable_EmptyRootName",
type: "POST",
data: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (data) {
alert(data.d) // showing json is fine
var MyData = $.parseJSON(data.d)[""];
for (i = 0; i < MyData.length; i++) {
alert(MyData[i].ID + ' : ' + MyData[i].MenuName);
}
}
});
}
]]