Javascript 大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口
我的代码是:Javascript 大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口大口,javascript,gulp,bower,Javascript,Gulp,Bower,我的代码是: var gulp = require('gulp'); var clean = require('gulp-clean'); var concat = require('gulp-concat'); var uglify = require('gulp-uglify'); var filter = require('gulp-filter'); var mainBowerFiles = require('main-bower-files'); var filterByExte
var gulp = require('gulp');
var clean = require('gulp-clean');
var concat = require('gulp-concat');
var uglify = require('gulp-uglify');
var filter = require('gulp-filter');
var mainBowerFiles = require('main-bower-files');
var filterByExtension = function(extension){
return filter(function(file){
return file.path.match(new RegExp('.' + extension + '$'));
});
};
gulp.task('third', function(){
var mainFiles = mainBowerFiles();
if(!mainFiles.length){
// No main files found. Skipping....
return;
}
var jsFilter = filterByExtension('js');
return gulp.src(mainFiles)
.pipe(jsFilter)
.pipe(concat('third-party.js'))
.pipe(gulp.dest('./app'))
.pipe(jsFilter.restore())
.pipe(filterByExtension('css'))
.pipe(concat('third-party.css'))
.pipe(gulp.dest('./app'));
});
“return file.path.match(new RegExp('.+扩展名+'$)”)中出现错误,但这应该可以工作。有什么建议吗
非常感谢。您的问题是过滤器函数中的返回类型。nodej和Gulp对通过管道的类型非常挑剔。你只需要一次意外的返回就可以打破链条 根据gulp filter,嵌套过滤器应返回布尔值,
String.prototype.match
将返回匹配结果数组,如果不匹配,则返回null。这足以破坏这个东西,因为它不需要数组
您可以使用返回布尔值的RegExp.prototype.test
,或者检查是否匹配(…).length>0
。一个可能的解决方案:
JS:
var filterByExtension = function(extension){
return filter(function(file){
var matches = file.path.match(new RegExp('.' + extension + '$'));
return matches && matches.length > 0;
});
};
它说了错误是什么吗?@Mark答案解决了问题吗?如果是,请将其标记为已接受:)