Jpa 具有两个相同类型字段的类之间的连接
我有以下课程:Jpa 具有两个相同类型字段的类之间的连接,jpa,join,Jpa,Join,我有以下课程: @Entity @Table(name = "entity") public class Entity extends Model { @ManyToMany(fetch = FetchType.EAGER) @JoinTable(name = "entity_owner", joinColumns = @JoinColumn(name = "entity_id"), inverseJoinColumns = @JoinColumn(n
@Entity
@Table(name = "entity")
public class Entity extends Model
{
@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(name = "entity_owner", joinColumns = @JoinColumn(name = "entity_id"), inverseJoinColumns = @JoinColumn(name = "user_id"))
private Set<UserAccount> owners;
@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(name = "entity_assignee", joinColumns = @JoinColumn(name = "entity_id"), inverseJoinColumns = @JoinColumn(name = "user_id"))
private Set<UserAccount> assignees;
}
有人能告诉我我做错了什么吗?如果UserAccount同时位于所有者和受让人中,则查询似乎会复制一个结果,您可以使用DISTINCT筛选重复的结果:
SELECT DISTINCT r FROM ...
当已有UserAccount实例可用于筛选结果时, 表达式可用于:
SELECT DISTINCT(e)
FROM SomeEntity e
WHERE :someUser MEMBER OF e.assignees OR
:someUser MEMBER OF e.owners
UserAccount ua ...
em.createQuery(jpql).setParameter("someUser", ua)
若由于某种原因,首选类似于原始查询的查询,那个么添加DISTINCT就足够了
SELECT DISTINCT(e)
FROM SomeEntity e
WHERE :someUser MEMBER OF e.assignees OR
:someUser MEMBER OF e.owners
UserAccount ua ...
em.createQuery(jpql).setParameter("someUser", ua)