jquery:如何延迟触发each()呢
如何延迟触发jquery:如何延迟触发each()呢,jquery,delay,each,Jquery,Delay,Each,如何延迟触发each() 这是一种代码,用于延迟每个框在给定的特定时间淡出 $(document).ready(function(){ var delay = 0; $('.block-item:lt(16)').each(function(){ //^^ do for every instance less than the 16th (starting at 0) $(this).delay(delay).animate({
each()
这是一种代码,用于延迟每个框在给定的特定时间淡出
$(document).ready(function(){
var delay = 0;
$('.block-item:lt(16)').each(function(){
//^^ do for every instance less than the 16th (starting at 0)
$(this).delay(delay).animate({
opacity:0
},500);
delay += 500;
});
});
但是我想在触发each()
之前延迟大约五秒钟。可行吗
这是一个例子。这是我专门为此做的一个片段。 您可以调用iniFadeChildren($('.parent'),'li',500) 所有的李都会一个接一个的消失
function iniFadeChildren(pParent, pChildrenType, pDelay, pSpeed){
pParent.find(pChildrenType).css({display:'none'});
if(!pChildrenType){pChildrenType='*'} if(!pDelay){pDelay=200} if(!pSpeed){pSpeed=300}
fadeChildren(pParent, pChildrenType, pDelay, 0, pParent.children(pChildrenType).length, pSpeed);
}
function fadeChildren(pParent, pChildrenType, pDelay, pNbr, pTotal, pSpeed){
pParent.find(pChildrenType).eq(pNbr).fadeIn(pSpeed);
pNbr++;
if(pNbr!=pTotal){
var command='fadeChildren('+pParent+', '+pChildrenType+', '+pDelay+', '+pNbr+', '+pTotal+')';
t=setTimeout(function(){fadeChildren(pParent, pChildrenType, pDelay, pNbr, pTotal, pSpeed)}, pDelay);
}
}
这是我专门为此做的一个片段。 您可以调用iniFadeChildren($('.parent'),'li',500) 所有的李都会一个接一个的消失
function iniFadeChildren(pParent, pChildrenType, pDelay, pSpeed){
pParent.find(pChildrenType).css({display:'none'});
if(!pChildrenType){pChildrenType='*'} if(!pDelay){pDelay=200} if(!pSpeed){pSpeed=300}
fadeChildren(pParent, pChildrenType, pDelay, 0, pParent.children(pChildrenType).length, pSpeed);
}
function fadeChildren(pParent, pChildrenType, pDelay, pNbr, pTotal, pSpeed){
pParent.find(pChildrenType).eq(pNbr).fadeIn(pSpeed);
pNbr++;
if(pNbr!=pTotal){
var command='fadeChildren('+pParent+', '+pChildrenType+', '+pDelay+', '+pNbr+', '+pTotal+')';
t=setTimeout(function(){fadeChildren(pParent, pChildrenType, pDelay, pNbr, pTotal, pSpeed)}, pDelay);
}
}
如果只是延迟初始动画,为什么不从5000延迟开始呢
如果只是延迟初始动画,为什么不从5000延迟开始呢 是的,你可以,像这样
$(document).ready(function(){
var delay = 0;
setTimeout(function() {
$('.block-item:lt(16)').each(function(){
//^^ do for every instance less than the 16th (starting at 0)
$(this).delay(delay).animate({
opacity:0
},500);
delay += 500;
});
}, 5000);
});
是的,你可以,像这样
$(document).ready(function(){
var delay = 0;
setTimeout(function() {
$('.block-item:lt(16)').each(function(){
//^^ do for every instance less than the 16th (starting at 0)
$(this).delay(delay).animate({
opacity:0
},500);
delay += 500;
});
}, 5000);
});
你的意思是在每个人第一次打电话之前等5秒钟吗?如果是这样,请使用
setTimeout
$(document).ready(function(){
var delay = 0;
// Wrap the function with setTimeout
setTimeout(function(){
$('.block-item:lt(16)').each(function(){
//^^ do for every instance less than the 16th (starting at 0)
$(this).delay(delay).animate({
opacity:0
},500);
delay += 500;
});
}, 5000); // 5000 = 5 seconds
});
你的意思是在每个人第一次打电话之前等5秒钟吗?如果是这样,请使用
setTimeout
$(document).ready(function(){
var delay = 0;
// Wrap the function with setTimeout
setTimeout(function(){
$('.block-item:lt(16)').each(function(){
//^^ do for every instance less than the 16th (starting at 0)
$(this).delay(delay).animate({
opacity:0
},500);
delay += 500;
});
}, 5000); // 5000 = 5 seconds
});
您可以使用
setInterval
方法来实现这一点
$(document).ready(function(){
var count = 0;
var $blockItems = $('.block-item:lt(16)');
var timer;
timer = setInterval(function(){
if(count == 16){
clearInterval(timer);
return;
}
$blockItems.eq(count).animate({
opacity:0
},500);
count++;
}, 500);
});
您可以使用
setInterval
方法来实现这一点
$(document).ready(function(){
var count = 0;
var $blockItems = $('.block-item:lt(16)');
var timer;
timer = setInterval(function(){
if(count == 16){
clearInterval(timer);
return;
}
$blockItems.eq(count).animate({
opacity:0
},500);
count++;
}, 500);
});
利用一些新特性
利用一些新特性
如果有人对如何改进这段代码有想法,那将是值得赞赏的。如果有人对如何改进这段代码有想法,那将是值得赞赏的。这是行不通的<代码>每个都不是动画,因此不会排队。因此,延迟不会延迟每个。这将不起作用<代码>每个都不是动画,因此不会排队。因此,延迟不会延迟每个。