Jquery 如果超过100，如何在字符串中间插入（…）

我有五个字符串变量，其中两个变量可以随时更改，其余三个变量是常量。现在我想计算<强>五个变量< /强>的长度，如果它超过100，那么在STR1，Str2字符串中，我希望插入（…）在字符串的中间。如果小于100，则不应发生任何事情 注意：再次追加（…）后，五个字符串的总长度不应超过100

//string values can be changed
var str1 = "Lorem Ipsum is simply dummy text of the printing and typesetting industry";
var str2 = "Lorem Ipsum is simply dummy text of the industry";

//Constant string values
var name1 = "Ramesh";
var name2 = "suresh";
var name3 = "Raj";

---

可能是这样的：

// this is code what i am having

$(".clickme").click(function(){
       var len = str1.length + str1.length + name1.length + name2.length + name3.length;
        if( len > 100 )
        {
            str1mid = str1.length / 2;
            str2mid = str2.length / 2;
            if(str1mid > 50)
            {
              str1mid = 50;
            }
            if(str2mid > 50)
            {
              str2mid = 50;
            }
            str1 = str1.substring(0,str1mid) + '...' + str1.substring(str1mid,100);
            str2 = str2.substring(0,str2mid) + '...' + str2.substring(str2mid,100);
            console.log(str1);
            console.log(str2);          
        }
        else
        {
            console.log(" Yes it is less then 100");
        }

   alert(len);
});

---

您可以使用str1.substring（0100）来trunc最大100个字符

我假设您的意思是缩短字符串并添加。。。到最后。这里有一个函数可以做到这一点

if(str1.length > 100)
{
   var middle = str1.length/2;
   str1 = str1.substring(0,middle) + '...' + str1.substring(middle);
}

您可以这样使用它：

function shorten(text) {
  if (text.length > 100) {
    return text.substring(0,97)+"...";
  } else {
    return text;
  }
}

---

您的问题使您看起来想要一件事，但是您的示例代码看起来想要其他东西。第一个函数是您的问题让它听起来像您想要的，第二个函数是您的示例代码似乎表明的

职能1：

var str1 = shorten("Lorem Ipsum is simply dummy text of the printing and typesetting industry");

函数capLength（str1、str2、name1、name2、name3）{
//连接字符串并获得结果长度。
//（这与str1+str2相同……只是稍微快一点。）
var totalLength=[str1，str2，name1，name2，name3]。连接（“”）。长度；
var excessLength=总长度-100；
if（超出长度str1.长度）{
str1长度--；
str2Length++；
}
while（str2Length>str2.length）{
str2长度--；
str1Length++；
}
str1=str1.子串（0，str1长度-3）+“…”；
str2=str2.子串（0，str2长度-3）+“…”；
返回[str1，str2，name1，name2，name3]；
}

职能2：

function capLength(str1, str2, name1, name2, name3) { 
  // Join the strings and get the resulting length.
  // (This is the same as str1 + str2... just marginally faster.)
  var totalLength = [str1, str2, name1, name2, name3].join("").length;

  var excessLength = totalLength - 100;
  if (excessLength <= 0) {
    return; // If the string isn't too long, no changes are needed.
  }

  // Available length for the variable strings (combined) will be
  // 100 - combined length of the constant strings.
  // To get the length of each one, we divide by two.
  var str1Length = (100 - name1.length - name2.length - name3.length) / 2;
  var str2Length = (100 - name1.length - name2.length - name3.length) / 2;

  // It's possible that one string will be under the limit and one will be over.
  // Move the available length from one to the other
  while (str1Length > str1.length) {
    str1Length--;
    str2Length++;
  }
  while (str2Length > str2.length) {
    str2Length--;
    str1Length++;
  }

  str1 = str1.substring(0, str1Length - 3) + "...";
  str2 = str2.substring(0, str2Length - 3) + "...";

  return [str1, str2, name1, name2, name3];
}

函数capLength（str1、str2、name1、name2、name3）{
//连接字符串并获得结果长度。
//（这与str1+str2相同……只是稍微快一点。）
var totalLength=[str1，str2，name1，name2，name3]。连接（“”）。长度；
var excessLength=总长度-100；
if（超出长度str1.长度）{
str1长度--；
str2Length++；
}
while（str2Length>str2.length）{
str2长度--；
str1Length++；
}
var str1Mid=str1.length/2；
var str2Mid=str2.length/2；
如果（str1.length！=str1长度）{
str1=（str1.子字符串（0，str1.length/2）+“…”）.子字符串（0，str1.length）；
}
如果（str2.length！=str2长度）{
str1=（str2.子字符串（0，str2.length/2）+“…”）.子字符串（0，str2.length）；
}
返回[str1，str2，name1，name2，name3]；
}

到目前为止，您尝试了什么？您是否有一些代码要共享（即使它目前不工作）？请小心定义这样的函数。如果使用

函数foo（）{}

，可以在任何地方调用它。如果使用

var foo=function（）{}

，则只能在定义之后调用它。这也将导致字符串长度为103。省略号为长度增加了3个字符。

function capLength(str1, str2, name1, name2, name3) { 
  // Join the strings and get the resulting length.
  // (This is the same as str1 + str2... just marginally faster.)
  var totalLength = [str1, str2, name1, name2, name3].join("").length;

  var excessLength = totalLength - 100;
  if (excessLength <= 0) {
    return; // If the string isn't too long, no changes are needed.
  }

  // Available length for the variable strings (combined) will be
  // 100 - combined length of the constant strings.
  // To get the length of each one, we divide by two.
  var str1Length = (100 - name1.length - name2.length - name3.length) / 2;
  var str2Length = (100 - name1.length - name2.length - name3.length) / 2;

  // It's possible that one string will be under the limit and one will be over.
  // Move the available length from one to the other
  while (str1Length > str1.length) {
    str1Length--;
    str2Length++;
  }
  while (str2Length > str2.length) {
    str2Length--;
    str1Length++;
  }

  var str1Mid = str1.length / 2;
  var str2Mid = str2.length / 2;

  if (str1.length != str1Length) {
    str1 = (str1.substring(0, str1.length / 2) + "...").substring(0, str1Length);
  }
  if (str2.length != str2Length) {
    str1 = (str2.substring(0, str2.length / 2) + "...").substring(0, str2Length);
  }

  return [str1, str2, name1, name2, name3];
}