用jq替换多个JSON对象的所有值
我正在尝试使用用jq替换多个JSON对象的所有值,json,foreach,key-value,jq,map-function,Json,Foreach,Key Value,Jq,Map Function,我正在尝试使用*(星号字符)替换JSON对象的所有值 这是我的package.json文件: { "name": "project", "version": "0.0.1", "description": "project-desc", "main": "gulpfile.js", "directories": { "test": "tests" }, "dependencies": { "babel-polyfill": "^6.7.4",
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(星号字符)替换JSON对象的所有值
这是我的package.json文件:
{
"name": "project",
"version": "0.0.1",
"description": "project-desc",
"main": "gulpfile.js",
"directories": {
"test": "tests"
},
"dependencies": {
"babel-polyfill": "^6.7.4",
"babel-preset-es2015": "^6.6.0",
"babel-preset-react": "^6.5.0",
"gulp-clean": "^0.3.2",
"jquery": "^2.1.4",
"lodash": "^4.0.0",
"moment": "^2.13.0",
"moment-timezone": "^0.5.0",
"radium": "^0.16.2",
"react": "^15.1.0",
"react-bootstrap-sweetalert": "^1.1.10",
"react-dom": "^15.1.0",
"react-timeago": "^2.2.1",
"sprintf": "^0.1.5",
"smoothscroll": "~0.2.2"
},
"devDependencies": {
"babel": "^6.3.26",
"babelify": "^7.2.0",
"browserify": "^12.0.1",
"console-stamp": "^0.2.0",
"estraverse-fb": "^1.3.1",
"gulp": "^3.9.0",
"gulp-concat": "^2.6.0",
"gulp-sass": "^2.1.1",
"gulp-sourcemaps": "^1.6.0",
"gulp-util": "^3.0.7",
"lodash": "^4.5.1",
"lodash.assign": "^3.2.0",
"lodash.isfunction": "^3.0.8",
"lodash.reduce": "^4.3.0",
"node-sass": "^3.4.2",
"react-bootstrap": "^0.29.4",
"react-intl": "^2.1.0",
"reactify": "^1.1.1",
"sweetalert": "^1.1.3",
"vinyl": "^1.1.0",
"vinyl-buffer": "^1.0.0",
"vinyl-source-stream": "^1.1.0",
"watchify": "^3.4.0",
"jsx-to-string": "~0.2.11"
},
"optionalDependencies": {
"pkg-save": "~1.0.2"
},
"scripts": {
"test": "echo \"Error: no test specified\" && exit 1"
},
"repository": {
"type": "git",
"url": "mygiturl"
},
"author": "authorname",
"license": "MIT"
}
我想用星号替换依赖项
、devdependency
和可选依赖项
对象的所有值,如下所示(以下简称示例):
这是我正在使用的过滤器:.dependencies、.devDependencies、.optionalDependencies |.foreach.[]作为$item([];$item=“*”)
在命令行中传递为:
cat package.json | jq'.dependencies、.devDependencies、.optionaldpendencies |.foreach.[]作为$item([];$item=“*”)”
但它返回了一个错误,而不是期望的结果:
error: syntax error, unexpected '[', expecting IDENT
.dependencies, .devDependencies, .optionalDependencies | .foreach .[] as $item ([]; $item = "*")
^
1 compile error
不仅仅是一个语法错误,我确信它只是操纵顶级项,而不是对象中的每个键值对,这正是我想要做的
参考资料和相关问题:
- 完成任务最直接的方法可能是使用以下过滤器:
.dependencies |=映射值(“*”)
|.devDependencies |=映射值(“*”)
|.optionalDependencies |=映射值(“*”)
为避免重复:
(.dependencies、.devDependencies、.optionalDependencies)|=映射值(“*”)
完成任务最直接的方法可能是使用以下过滤器:
.dependencies |=映射值(“*”)
|.devDependencies |=映射值(“*”)
|.optionalDependencies |=映射值(“*”)
为避免重复:
(.dependencies、.devDependencies、.optionalDependencies)|=映射值(“*”)
利用逗号运算符,您可以一次性更新所有内容。要将所有值更新为“*”
,可以执行以下操作:
.["dependencies", "devDependencies", "optionalDependencies"] |= map_values("*")
您可以利用逗号运算符一下子更新所有内容。要将所有值更新为
“*”
,可以执行以下操作:
.["dependencies", "devDependencies", "optionalDependencies"] |= map_values("*")