使用Python在列表中将重复的JSON键值对分组在一起

我已从REST API读取并过滤了所需的数据，如下所示：

 [[key,value] for groups in results for group in groups['results'] for key,value in group.items() if key in ['utc_offset','country','city','state','name','link','lat','lon']]

我的输出：

[['utc_offset', -14400000],
['country', 'CA'],
['city', 'Toronto'],
['link', 'https://www.meetup.com/slashdot-3/'],
['lon', -79.44000244140625],
['name', 'The Toronto Slashdot Meetup Group'],
['state', 'ON'],
['lat', 43.7599983215332],
['utc_offset', -14400000],
['country', 'CA'],
['city', 'Toronto'],
['link', 'https://www.meetup.com/webcentric/'],
['lon', -79.44000244140625],
['name', 'The Greater Toronto Web Centric Meetup Group'],
['state', 'ON'],
['lat', 43.7599983215332],
['utc_offset', -14400000],
['country', 'CA'],
['city', 'Toronto'],
['link', 'https://www.meetup.com/php-27/'],
['lon', -79.37999725341797],
['name', 'The Toronto PHP Meetup Group'],
['state', 'ON'],
.
.
.
]]

我试图对重复键进行分组，这样就可以将它们建模为Django的数据对象：

[['utc_offset', -14400000],['country', 'CA'],['city', 'Toronto'],['link', 'https://www.meetup.com/slashdot-3/'],['lon', -79.44000244140625],['name', 'The Toronto Slashdot Meetup Group'],['state', 'ON'],['lat', 43.7599983215332]]

我试过这个：

[zip(range(8),[key,value]) for groups in results for group in groups['results'] for key,value in group.items() if key in ['utc_offset','country','city','state','name','link','lat','lon']]

但我的输出是：

<zip object at 0x00000228D3C2F388>
<zip object at 0x00000228D3C2F388>
<zip object at 0x00000228D3C2F388>
<zip object at 0x00000228D3C2F388>
<zip object at 0x00000228D3C2F388>
<zip object at 0x00000228D3C2F3C8>
<zip object at 0x00000228D3C2F3C8>
<zip object at 0x00000228D3C2F3C8>
<zip object at 0x00000228D3C2F3C8>
<zip object at 0x00000228D3C2F388>
 .
 .
 .
 # twice the amount of the records I already have

.
.
.
#是我现有记录的两倍

所以这几乎不是答案，所以任何帮助都会很好。谢谢

编辑 我期望的输出是这样的

['utc_offset'，value]，'country'，value]，'city'，value]，'link'，value]，'lon'，value]，'name'，value]，'state'，value]，'lat'，value]，

我想这就是你想要的（我仍然不能100%确定你想让我对每个结果块做什么）：

其结果是：

[
    [
        ['utc_offset', -14400000], 
        ['country', 'CA'], 
        ['city', 'Toronto'], 
        ['link', 'https://www.meetup.com/slashdot-3/'], 
        ['lon', -79.44000244140625], 
        ['name', 'The Toronto Slashdot Meetup Group'], 
        ['state', 'ON'], 
        ['lat', 43.7599983215332]
    ], 
    [
        ['utc_offset', -14400000], 
        ['country', 'CA'], 
        ['city', 'Toronto'], 
        ['link', 'https://www.meetup.com/webcentric/'], 
        ['lon', -79.44000244140625], 
        ['name', 'The Greater Toronto Web Centric Meetup Group'], 
        ['state', 'ON'], 
        ['lat', 43.7599983215332]
    ]
]

---

utc_offset

到

lat

的每个块都被放入自己的列表中。如果您需要其他格式的文件，请告诉我。

您能更具体地说明您想要的输出吗？例如，

链接

键有多个值。您希望如何处理每个值？像

['link'、'link 1'、'link 2']

，或者作为一个dict，或者其他形式？嘿！！我没想到会有人这么快找到我。每个键值对都是唯一的，我试着把它们排成一行，这样我就可以把它们放到数据库中。我会编辑我的帖子。无论你用什么格式把它们排成一行都可以：）谢谢！！我用装饰器、生成器和理解功能编写Python只有几个星期，所以我从来没有想到过这一点。我会给你更多的分数，但现在它甚至不让我给你+1！

[
    [
        ['utc_offset', -14400000], 
        ['country', 'CA'], 
        ['city', 'Toronto'], 
        ['link', 'https://www.meetup.com/slashdot-3/'], 
        ['lon', -79.44000244140625], 
        ['name', 'The Toronto Slashdot Meetup Group'], 
        ['state', 'ON'], 
        ['lat', 43.7599983215332]
    ], 
    [
        ['utc_offset', -14400000], 
        ['country', 'CA'], 
        ['city', 'Toronto'], 
        ['link', 'https://www.meetup.com/webcentric/'], 
        ['lon', -79.44000244140625], 
        ['name', 'The Greater Toronto Web Centric Meetup Group'], 
        ['state', 'ON'], 
        ['lat', 43.7599983215332]
    ]
]