Json swift-在谷歌图像中搜索时，在展开可选值时意外发现nil

看起来，当我想从谷歌图片中抓取一张图片时，它不会起作用。有人能找出我做错了什么吗

您的URL格式不正确。删除纽约和纽约之间的空格。

您需要对URL进行编码：并停止强制展开选项。

let placeName = "New York"

func getImage(place: String) {
let url = NSURL(string: "https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=\(place)")
let request = NSURLRequest(URL: url!)
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()){ (response, go, error) -> Void in
    do {
        let go = try NSJSONSerialization.JSONObjectWithData(go!, options: NSJSONReadingOptions.AllowFragments) as! [String:AnyObject]
        let responseData = go["responseData"] as! [String:AnyObject]
        let results = responseData["results"] as! [[String:String]]
        let firstObject = results[0]
        let firstURL = firstObject["unescapedUrl"]
        print(responseData)
    } catch{
        print(error)
    }

  }
}

getImage(placeName)