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无法将request.getParameter()从servlet写入jsp_Jsp_Servlets - Fatal编程技术网

无法将request.getParameter()从servlet写入jsp

无法将request.getParameter()从servlet写入jsp,jsp,servlets,Jsp,Servlets,我正在将包含数据的html表从servlet发送到我的jsp页面。我的servlet代码如下所示: String html = "<table><thead><th>Serial</th><th>MAC</th></thead>" + "<tbody> + "<tr>1000234<td></td><td

我正在将包含数据的html表从servlet发送到我的jsp页面。我的servlet代码如下所示:

String html = "<table><thead><th>Serial</th><th>MAC</th></thead>"
              + "<tbody>
              + "<tr>1000234<td></td><td>9845HM98</td></tr>"
              + "<tbody>"
              + "</table>";

request.setAttribute("responselDetails", html);

ServletContext context= getServletContext();
RequestDispatcher rd= context.getRequestDispatcher("/jsp/Details.jsp");
rd.forward(request, response);
String html=“SerialMAC”
+ "
+“10002349845HM98”
+ ""
+ "";
setAttribute(“responsedeletails”,html);
ServletContext=getServletContext();
RequestDispatcher rd=context.getRequestDispatcher(“/jsp/Details.jsp”);
转发(请求、响应);
jsp:


似乎将
request.setParameter()
request.setAttribute()

您正在servlet中设置
request.setAttribute()
,并试图通过jsp中的
request.getParameter()
访问它,jsp中总是给出nullPointer异常

快速修复:在jsp中将
getParameter()
更正为
getAttribute()
,您就完成了:-)



哦,我错过了这件小事。谢谢你救了我的命。请解释你遇到的错误类型。没有例外或错误,但不要打印任何内容。@David的回答解决了我的问题。谢谢
<% if (request.getParameter("responsePeripheralDetails") != null) { %>
<%= request.getParameter("responsePeripheralDetails") %>
<% } %>
<% if (request.getAttribute("responsePeripheralDetails") != null) { %>
<%= request.getAttribute("responsePeripheralDetails") %>
<% } %>