Laravel 4 如何在Laravel中保存多对多多态关系中的条目?
我有一个组织模型和一个标签模型。我想将标签与组织相关联。我的数据库表和雄辩的模型是这样设置的Laravel 4 如何在Laravel中保存多对多多态关系中的条目?,laravel-4,eloquent,polymorphic-associations,Laravel 4,Eloquent,Polymorphic Associations,我有一个组织模型和一个标签模型。我想将标签与组织相关联。我的数据库表和雄辩的模型是这样设置的 org id - integer name - string ... tags id - integer name - string taggables id - integer taggable_id - integer taggable_type - string // app/models/Org.php class Org e
org
id - integer
name - string
...
tags
id - integer
name - string
taggables
id - integer
taggable_id - integer
taggable_type - string
// app/models/Org.php
class Org extends Eloquent
{
protected $table = "org";
...
public function tags()
{
return $this->morphToMany('Tag', 'taggable');
}
}
// app/models/Tag.php
class Tag extends Eloquent
{
protected $table = "tags";
public $timestamps = false;
public function org()
{
return $this->morphedByMany('Org', 'taggable');
}
}
在我看来,我有一个带有多个选择框的表单,用户可以在其中选择他/她希望与组织关联的标签
...
{{ Form::select('tags[]', $tag_options, null, array(
'multiple',
'data-placeholder' => 'Select some tags'))
}}
...
。。。$tag_选项来自我的routes.php文件
View::composer('*', function($view)
{
$tags = Tag::all();
if(count($tags) > 0)
{
$tag_options = array_combine($tags->lists('id'),
$tags->lists('name'));
}
else
{
$tag_options = array(null, 'Unspecified');
}
$view->with('tag_options', $tag_options);
});
提交我视图中的表单时,以下路径将捕获它以更新组织模型
Route::put('org/{org}', function(Org $org){
$org->description = Input::get('description');
$org->website = Input::get('website');
$org->tags = Input::get('tags');
$org->save();
return Redirect::to('org/'.$org->id)
->with('message', 'Seccessfully updated page!');
});
现在,Input::get('tags')只是一个标签ID数组,形式如下
["1","6","8"]
如何使用它将标记与组织关联
我还为使用多态关系的组织设置了评论,我只是这样做
Route::put('org/post/{org}', function(Org $org){
$comment = new Comment;
$comment->user_id = Auth::user()->id;
$comment->body = Input::get('body');
$comment->commentable_id = $org->id;
$comment->commentable_type = 'Org';
$comment->save();
return Redirect::to('org/'.$org->id)
->with('message', 'Seccessfully posted comment!');
});
然而,当我想将一个或多个标记与一个组织关联时,多对多多态关系并不是那么简单
非常感谢您的帮助,谢谢 您可以使用所有的
belongtomany
方法,因为多态多对多扩展了这种关系:
// I would call that relation on tag in plural 'entities()' to be more accurate
$tag->entities()->save(new or existing model, array of pivot data, touch parent = true) (used on existing model)
$tag->entities()->saveMany(array of new or existing models, array of arrays with pivot data)
$tag->entities()->attach(existing model / id, array of pivot data, touch parent = true)
$tag->entities()->sync(array of ids, detach = true)
$tag->entities()->updateExistingPivot(pivot id, array of pivot data, touch)
当然,所有这些方法都是双向的
示例:
$tag = Tag::first();
$entity = Entity::find(10);
// save() works with both newly created and existing models:
$tag->entities()->save(new Entity(...));
$tag->entities()->save($entity);
// saveMany() like above works with new and/or existing models:
$tag->entities()->saveMany([$entity, new Entity(...)]);
// attach() works with existing model or its id:
$tag->entities()->attach($entity);
$tag->entities()->attach($entity->id);
// sync() works with existing models' ids:
$tag->entities()->sync([1,5,10]); // detaches all previous relations
$tag->entities()->sync([1,5,10], false); // does not detach previous relations, attaches new ones skipping existing ids
你的情况:
Route::put('org/{org}', function(Org $org){
$org->description = Input::get('description');
$org->website = Input::get('website');
$org->save();
$org->tags()->sync(Input::get('tags'));
// or if you don't want to detach previous tags:
// $org->tags()->sync(Input::get('tags'), false);
return Redirect::to('org/'.$org->id)
->with('message', 'Seccessfully updated page!');
});
这对我没什么帮助。你能举一个例子,说明我如何在这种情况下使用它吗?我已经更新了我的问题,所以应该更清楚一点(希望如此)。所以问题是如何将标签的ID数组与组织同步?那么我的回答就涵盖了这一点。无论如何,请稍后检查编辑。@Victor
save
和attach
可能会创建重复项sync
永远不会这样做,不管有没有$detach=false
标志。@JarekTkaczyk laravel是否也使用sync在tagables表中插入值???@Saugathapa您尝试过吗?你得到了什么结果?