Laravel 在Relationship表中选择特定字段

我试图在3个不同的表中选择一些字段，我不知道我是否必须使用查询构建器（我宁愿避免使用它），或者我可能在我的模型上犯了错误

这是我的查询代码

$lobbies = Lobby::with(array('games' => function($query) {
    $query->select('id','name');
}))
->with(array('users' => function($query){
    $query->select('id', 'pseudo');
}))
->get();

return response()->json($lobbies);

它返回以下内容：

[
   {
      "id":2,
      "description":"mon premier lobby",
      "created_at":"2020-05-13 12:02:36",
      "support_link":"https:\/\/discord.gg\/K3NGfv4",
      "nb_player":1,
      "user_id":1,
      "game_id":2,
      "games":{
         "name":"Counter-strike"
      },
      "users":{
         "id":1,
         "pseudo":"misakilou"
      }
   }
]

但我只需要描述、名称（游戏名称）、nb_播放器和伪字段，而不需要其他字段

这是我的不同型号

用户模型

<?php

namespace App;

use Illuminate\Contracts\Auth\MustVerifyEmail;
use Illuminate\Foundation\Auth\User as Authenticatable;
use Illuminate\Notifications\Notifiable;
use Illuminate\Support\Facades\App;
use Illuminate\Database\Eloquent\Model;

class User extends Authenticatable
{
    use Notifiable;

    protected $table = 'users';

    /**
     * The attributes that are mass assignable.
     *
     * @var array
     */
    protected $fillable = [
        'pseudo', 'mail', 'password','active','confirm_password'
    ];

    /**
     * The attributes that should be hidden for arrays.
     *
     * @var array
     */
    protected $hidden = [
        'password', 'remember_token',
    ];

    /**
     * The attributes that should be cast to native types.
     *
     * @var array
     */
    protected $casts = [
        'email_verified_at' => 'datetime',
    ];

    public function lobbies(){
        return $this->hasOne('App\Lobby');
    }

    public function getUsernameAttribute(){
        return $this->pseudo;
    }
}

---

您可以将
选择
添加到
大厅
模型中，但请记住，您必须选择外键才能使用
工作。如果不希望该数据包含在响应中，可以映射查询返回的集合，以便在返回响应之前对其进行自定义。大概是这样的：

$lobbies = Lobby::select('id', 'description', 'nb_player', 'game_id', 'user_id')
->with(array('games' => function($query) {
    $query->select('id','name');
}))
->with(array('users' => function($query){
    $query->select('id', 'pseudo');
}))
->get();

$response = $lobbies->map(function ($lobby, $key) {
    $item = [
        'description' => $lobby->description,
        'nb_player' => $lobby->nb_player,
        'game_name' => $lobby->games->name,
        'user_pseudo' => $lobby->users->pseudo,
    ];
    return $item;
});

return response()->json($response);

$lobbies = Lobby::join('users', 'users.id', '=', 'lobbies.user_id')
            ->join('games', 'games.id', '=', 'lobbies.game_id')
            ->select('lobbies.description', 'lobbies.nb_player', 'users.pseudo', 'games.name')
            ->get();

return response()->json($lobbies);

如果要避免在集合上进行后续映射，可以使用联接而不是Eloquent的关系。大概是这样的：

$lobbies = Lobby::select('id', 'description', 'nb_player', 'game_id', 'user_id')
->with(array('games' => function($query) {
    $query->select('id','name');
}))
->with(array('users' => function($query){
    $query->select('id', 'pseudo');
}))
->get();

$response = $lobbies->map(function ($lobby, $key) {
    $item = [
        'description' => $lobby->description,
        'nb_player' => $lobby->nb_player,
        'game_name' => $lobby->games->name,
        'user_pseudo' => $lobby->users->pseudo,
    ];
    return $item;
});

return response()->json($response);

$lobbies = Lobby::join('users', 'users.id', '=', 'lobbies.user_id')
            ->join('games', 'games.id', '=', 'lobbies.game_id')
            ->select('lobbies.description', 'lobbies.nb_player', 'users.pseudo', 'games.name')
            ->get();

return response()->json($lobbies);

使用join将在查询到DB时具有更好的性能，并且还可以避免以后的映射。我保留了雄辩的人际关系选项，只是为了遵循你一直在做的事情。