Laravel 如何在查询生成器中创建此句子

我有一个问题，我需要在query builder中执行此查询：

SELECT
ps_orders.id_order,
ps_customer.firstname,
ps_customer.lastname,
ps_customer.email,
ps_address.address1,
ps_address.postcode,
ps_address.city,
ps_address.phone_mobile,
ps_orders.id_order,
ps_orders.reference,
ps_order_detail.product_name,
ps_order_detail.product_quantity,
ps_shop.name AS tienda,
ps_carrier.name AS transportista
FROM
ps_customer
INNER JOIN ps_address ON ps_customer.id_customer = ps_address.id_customer
INNER JOIN ps_orders ON ps_address.id_customer =              
ps_orders.id_customer AND ps_orders.id_address_delivery = 
ps_address.id_address
INNER JOIN ps_order_detail ON ps_orders.id_order = 
ps_order_detail.id_order
INNER JOIN ps_shop ON ps_order_detail.id_shop = ps_shop.id_shop                            
INNER JOIN ps_carrier ON ps_orders.id_carrier = ps_carrier.id_carrier                            
WHERE
ps_orders.id_order =54

$naviones=DB::connection('naviones')->table('ps_customer')
                ->join('ps_address','ps_customer.id_customer','=','ps_address.id_customer')
               ->join('ps_orders','ps_address.id_customer','=','ps_orders.id_customer')
                ->join('ps_order_detail','ps_orders.id_order','=','ps_order_detail.id_order')
                ->join('ps_shop','ps_order_detail.id_shop','=','ps_shop.id_shop')
                ->join('ps_carrier','ps_orders.id_carrier','=','ps_carrier.id_carrier')
                ->select('ps_orders.id_address_delivery','ps_orders.id_order','ps_customer.firstname','ps_customer.lastname','ps_customer.email','ps_address.address1',
                    'ps_address.postcode','ps_address.city','ps_address.phone_mobile','ps_orders.id_order','ps_orders.reference',
                    'ps_order_detail.product_name','ps_order_detail.product_quantity','ps_shop.name as tienda','ps_carrier.name as transportista')
                ->where('ps_orders.id_order','=',$idpedido)->get();

我在查询生成器中执行了此查询：

SELECT
ps_orders.id_order,
ps_customer.firstname,
ps_customer.lastname,
ps_customer.email,
ps_address.address1,
ps_address.postcode,
ps_address.city,
ps_address.phone_mobile,
ps_orders.id_order,
ps_orders.reference,
ps_order_detail.product_name,
ps_order_detail.product_quantity,
ps_shop.name AS tienda,
ps_carrier.name AS transportista
FROM
ps_customer
INNER JOIN ps_address ON ps_customer.id_customer = ps_address.id_customer
INNER JOIN ps_orders ON ps_address.id_customer =              
ps_orders.id_customer AND ps_orders.id_address_delivery = 
ps_address.id_address
INNER JOIN ps_order_detail ON ps_orders.id_order = 
ps_order_detail.id_order
INNER JOIN ps_shop ON ps_order_detail.id_shop = ps_shop.id_shop                            
INNER JOIN ps_carrier ON ps_orders.id_carrier = ps_carrier.id_carrier                            
WHERE
ps_orders.id_order =54

$naviones=DB::connection('naviones')->table('ps_customer')
                ->join('ps_address','ps_customer.id_customer','=','ps_address.id_customer')
               ->join('ps_orders','ps_address.id_customer','=','ps_orders.id_customer')
                ->join('ps_order_detail','ps_orders.id_order','=','ps_order_detail.id_order')
                ->join('ps_shop','ps_order_detail.id_shop','=','ps_shop.id_shop')
                ->join('ps_carrier','ps_orders.id_carrier','=','ps_carrier.id_carrier')
                ->select('ps_orders.id_address_delivery','ps_orders.id_order','ps_customer.firstname','ps_customer.lastname','ps_customer.email','ps_address.address1',
                    'ps_address.postcode','ps_address.city','ps_address.phone_mobile','ps_orders.id_order','ps_orders.reference',
                    'ps_order_detail.product_name','ps_order_detail.product_quantity','ps_shop.name as tienda','ps_carrier.name as transportista')
                ->where('ps_orders.id_order','=',$idpedido)->get();

我的问题是：我该如何处理这个查询部分

INNER JOIN ps_orders ON ps_address.id_customer =              
ps_orders.id_customer AND ps_orders.id_address_delivery = 
ps_address.id_address

---

我希望你能帮助我。谢谢。

您可以使用类似的方式加入

->join('table2 AS b', function($join){
        $join->on('a.field1', '=', 'b.field2')
        ->where('b.field3', '=', true)
        ->where('b.field4', '=', '1');
})

如果您不想进行比较，那么可以使用如下所示的多个链式函数

$query->join('ps_orders', function($join)
 {
   $join->on('ps_orders.id', '=', 'ps_address.id_customer')
        ->on('ps_orders.id_address_delivery', '=', 'ps_address.id_address')

 });

---

您可以在join函数中使用回调函数并传递两个相等条件。您好，您能举个例子吗？在文档中，我没有发现任何类似的问题。请检查我的答案是否可以帮助您。我想我已经解决了这个问题。我马上告诉你我是否能解决这个问题。这对其他人也有帮助。嗨，谢谢你回复我，这个方法对我没用，因为我需要比较我在这个查询中是如何做的：内部连接ps_orders ON ps_address.id_customer=ps_orders.id_customer和ps_orders.id_address\u delivery=ps_address.id_address.id_address在您告诉我的示例中的问题是，在需要子句的情况下，无法将一个域与其他域进行比较菲尔德嗨，是的，这是正确的答案，我在发布解决方案，但你在写解决方案。谢谢everybodyAlso非常重要，如果您使用函数$join，但需要与任何值进行比较并获得任何变量的此值，则可以使用保留方法将变量传递给函数$join，例如：函数$join使用$variable{}；我需要将一个变量传递给函数$join，但我不知道怎么做。是的，我知道这就是为什么我在第一个答案中只与table.field值、1或true值进行比较。