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Latex 将三个回归表附加到单独的面板中

latex stata

Latex 将三个回归表附加到单独的面板中,latex,stata,Latex,Stata,考虑以下玩具数据： input strL Country Population Median_Age Sex_Ratio GDP Trade year "United States of America" 3999 55 1.01 5000 13.1 2012 "United States of America" 6789 43 1.03 7689 7.6 2013 "United States of America" 9654 39 1.00 7689 4.04 2014 "Afghanist

考虑以下玩具数据：

input strL Country Population Median_Age Sex_Ratio GDP Trade year
"United States of America" 3999 55 1.01 5000 13.1 2012
"United States of America" 6789 43 1.03 7689 7.6 2013
"United States of America" 9654 39 1.00 7689 4.04 2014
"Afghanistan" 544 24 0.76 457 -0.73 2012
"Afghanistan" 720 19 0.90 465 -0.76 2013
"Afghanistan" 941 17 0.92 498 -0.81 2014
"China" 7546 44 1.01 2000 10.2 2012
"China" 10000 40 0.96 3400 14.3 2013
"China" 12000 38 0.90 5900  16.1 2014
"Canada" 7546 44 1.01 2000 1.2 2012
"Canada" 10000 40 0.96 3400 3.1 2013
"Canada" 12000 38 0.90 5900  8.5 2014
end
我运行不同的回归（使用三个不同的自变量）：

我使用
append
选项来追加要在同一组自变量上回归的不同因变量。因此，我得到了三个不同的表

当我在
LaTeX
中编译时，我希望“合并”这些表，以便它们显示为一个表，有三个不同的面板，一个在另一个下面

Table1
Table2
Table3
我可以使用社区贡献命令的
tex（frag）
选项
outreg2
，但这不会给我期望的结果。

下面是一个简单的方法，使用社区贡献命令
esttab
：

clear

input strL Country Population Median_Age Sex_Ratio GDP Trade year
"United States of America" 3999 55 1.01 5000 13.1 2012
"United States of America" 6789 43 1.03 7689 7.6 2013
"United States of America" 9654 39 1.00 7689 4.04 2014
"Afghanistan" 544 24 0.76 457 -0.73 2012
"Afghanistan" 720 19 0.90 465 -0.76 2013
"Afghanistan" 941 17 0.92 498 -0.81 2014
"China" 7546 44 1.01 2000 10.2 2012
"China" 10000 40 0.96 3400 14.3 2013
"China" 12000 38 0.90 5900  16.1 2014
"Canada" 7546 44 1.01 2000 1.2 2012
"Canada" 10000 40 0.96 3400 3.1 2013
"Canada" 12000 38 0.90 5900  8.5 2014
end

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Population i.year 
    matrix I = e(b)
    matrix A = nullmat(A) \ I[1,1]
    local namesA `namesA' Population_`ii'
}

matrix rownames A = `namesA'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Median_Age i.year 
    matrix I = e(b)
    matrix B = nullmat(B) \ I[1,1]
    local namesB `namesB' Median_Age_`ii'
}

matrix rownames B = `namesB'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Sex_Ratio i.year 
    matrix I = e(b)
    matrix C = nullmat(C) \ I[1,1]
    local namesC `namesC' Sex_Ratio_`ii'
}

matrix rownames C = `namesC'

matrix D = A \ B \ C
结果:

esttab matrix(D), refcat(Population_GDP "Panel 1" ///
                         Median_Age_GDP "Panel 2" ///
                         Sex_Ratio_GDP "Panel 3", nolabel) ///
                         gaps noobs nomtitles ///
                         varwidth(20) ///
                         title(Table 1. Results)

Table 1. Results
---------------------------------
                               c1
---------------------------------
Panel 1                          

Population_GDP           .3741343

Population_Trade         .0009904

Panel 2                          

Median_Age_GDP           202.1038

Median_Age_Trade          .429315

Panel 3                          

Sex_Ratio_GDP            18165.85

Sex_Ratio_Trade            27.965
---------------------------------
使用
tex
选项：

\begin{table}[htbp]\centering
\caption{Table 1. Results}
\begin{tabular}{l*{1}{c}}
\hline\hline
                    &          c1\\
\hline
Panel 1             &            \\
[1em]
Population\_GDP      &    .3741343\\
[1em]
Population\_Trade    &    .0009904\\
[1em]
Panel 2             &            \\
[1em]
Median\_Age\_GDP      &    202.1038\\
[1em]
Median\_Age\_Trade    &     .429315\\
[1em]
Panel 3             &            \\
[1em]
Sex\_Ratio\_GDP       &    18165.85\\
[1em]
Sex\_Ratio\_Trade     &      27.965\\
\hline\hline
\end{tabular}
\end{table}
编辑：

这将保留原始格式：

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Population i.year 
    matrix I = e(b)
    matrix A = (nullmat(A) , I[1,1])
    local namesA `namesA' `ii'
}

matrix rownames A = Population
matrix colnames A = `namesA'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Median_Age i.year 
    matrix I = e(b)
    matrix B = nullmat(B) , I[1,1]
    local namesB `namesB' `ii'
}

matrix rownames B = "Median Age"
matrix colnames B = `namesB'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Sex_Ratio i.year 
    matrix I = e(b)
    matrix C = nullmat(C) , I[1,1]
    local namesC `namesC' `ii'
}

matrix rownames C = "Sex Ratio"
matrix colnames C = `namesC'

matrix D = A \ B \ C

下面是一个简单的方法，使用社区贡献的命令
esttab
：

clear

input strL Country Population Median_Age Sex_Ratio GDP Trade year
"United States of America" 3999 55 1.01 5000 13.1 2012
"United States of America" 6789 43 1.03 7689 7.6 2013
"United States of America" 9654 39 1.00 7689 4.04 2014
"Afghanistan" 544 24 0.76 457 -0.73 2012
"Afghanistan" 720 19 0.90 465 -0.76 2013
"Afghanistan" 941 17 0.92 498 -0.81 2014
"China" 7546 44 1.01 2000 10.2 2012
"China" 10000 40 0.96 3400 14.3 2013
"China" 12000 38 0.90 5900  16.1 2014
"Canada" 7546 44 1.01 2000 1.2 2012
"Canada" 10000 40 0.96 3400 3.1 2013
"Canada" 12000 38 0.90 5900  8.5 2014
end

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Population i.year 
    matrix I = e(b)
    matrix A = nullmat(A) \ I[1,1]
    local namesA `namesA' Population_`ii'
}

matrix rownames A = `namesA'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Median_Age i.year 
    matrix I = e(b)
    matrix B = nullmat(B) \ I[1,1]
    local namesB `namesB' Median_Age_`ii'
}

matrix rownames B = `namesB'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Sex_Ratio i.year 
    matrix I = e(b)
    matrix C = nullmat(C) \ I[1,1]
    local namesC `namesC' Sex_Ratio_`ii'
}

matrix rownames C = `namesC'

matrix D = A \ B \ C
结果:

esttab matrix(D), refcat(Population_GDP "Panel 1" ///
                         Median_Age_GDP "Panel 2" ///
                         Sex_Ratio_GDP "Panel 3", nolabel) ///
                         gaps noobs nomtitles ///
                         varwidth(20) ///
                         title(Table 1. Results)

Table 1. Results
---------------------------------
                               c1
---------------------------------
Panel 1                          

Population_GDP           .3741343

Population_Trade         .0009904

Panel 2                          

Median_Age_GDP           202.1038

Median_Age_Trade          .429315

Panel 3                          

Sex_Ratio_GDP            18165.85

Sex_Ratio_Trade            27.965
---------------------------------
使用
tex
选项：

\begin{table}[htbp]\centering
\caption{Table 1. Results}
\begin{tabular}{l*{1}{c}}
\hline\hline
                    &          c1\\
\hline
Panel 1             &            \\
[1em]
Population\_GDP      &    .3741343\\
[1em]
Population\_Trade    &    .0009904\\
[1em]
Panel 2             &            \\
[1em]
Median\_Age\_GDP      &    202.1038\\
[1em]
Median\_Age\_Trade    &     .429315\\
[1em]
Panel 3             &            \\
[1em]
Sex\_Ratio\_GDP       &    18165.85\\
[1em]
Sex\_Ratio\_Trade     &      27.965\\
\hline\hline
\end{tabular}
\end{table}
编辑：

这将保留原始格式：

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Population i.year 
    matrix I = e(b)
    matrix A = (nullmat(A) , I[1,1])
    local namesA `namesA' `ii'
}

matrix rownames A = Population
matrix colnames A = `namesA'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Median_Age i.year 
    matrix I = e(b)
    matrix B = nullmat(B) , I[1,1]
    local namesB `namesB' `ii'
}

matrix rownames B = "Median Age"
matrix colnames B = `namesB'

local var "GDP Trade"
foreach ii of local var{
    regress `ii' Sex_Ratio i.year 
    matrix I = e(b)
    matrix C = nullmat(C) , I[1,1]
    local namesC `namesC' `ii'
}

matrix rownames C = "Sex Ratio"
matrix colnames C = `namesC'

matrix D = A \ B \ C

我的原始代码将因变量（GDP、贸易）列为Col1和Col2，自变量（人口）列为行。我想保持这种格式，pleasemy的原始代码将因变量（GDP、贸易）列为Col1和Col2，自变量（人口）列为行。我想保持这种格式