Linux 允许用户仅选择一组显示的ID

我真的不知道这叫什么，所以是的，基本上我想让用户只选择显示的ID（见图）。我正在考虑使用一个变量并将这些数字作为数组保存，但我不知道，因为我还在学习bash脚本。谢谢大家!

我的剧本是这样的

read -p "Select accessory category below."
mysql -D snipeit -e "SELECT id AS ID, name AS Name FROM categories WHERE category_type='accessory';"
read -p "Accessory category: " accessoryCateg
if *(allow only 4, 5, 7, 8, 9, 10, 11, 12, 13, 14 to be selected)*
*inserts data into database*
else echo "Try again!"
fi

---

您可以尝试使用

选择
命令：

echo "Select accessory category below."
sample1=`mysql -D snipeit -e "SELECT id AS ID FROM categories WHERE category_type='accessory';"`
options=(`echo $sample1 | cut -d ' ' -f2-`)

PS3="Please select a category: "
select accessoryCateg in "${options[@]}"
do
echo "selected $accessoryCateg"
#inserts data into database
break;
done

我用计算机解决了这个问题

echo "Select accessory category below."
mysql -D snipeit -e "SELECT id AS ID, name AS Name FROM categories WHERE category_type='accessory';"
read -p "Accessory category: " userAccCateg
varAccCateg=$(mysql -D snipeit -e "SELECT id FROM categories WHERE category_type='accessory';")
accCateg=(`echo $varAccCateg | cut -d ' ' -f2-`)

if [[ " ${accCateg[@]} " =~ " ${userAccCateg} " ]]; then
    echo "You have chosen $userAccCateg"
else
    echo "Wrong choice!"
fi

结果是这样的


感谢@zhliu03和@sjsam的帮助
 谢谢你，我会试试这个，如果有问题我会报告的works@PauloBernardo：谢谢，非常感谢我今天才注意到，我应该把这件事放在哪里？在您的代码中，您已完成2项，但只有1项。您的代码将在下面显示“选择附件类别”。1） 4 5 7 8 9 10 11 12 13 14请选择一个类别：4 selectedoh，带有选项的行=。。。需要更改，我已经编辑了我以前的帖子。
echo "Select accessory category below."
mysql -D snipeit -e "SELECT id AS ID, name AS Name FROM categories WHERE category_type='accessory';"
read -p "Accessory category: " userAccCateg
varAccCateg=$(mysql -D snipeit -e "SELECT id FROM categories WHERE category_type='accessory';")
accCateg=(`echo $varAccCateg | cut -d ' ' -f2-`)

if [[ " ${accCateg[@]} " =~ " ${userAccCateg} " ]]; then
    echo "You have chosen $userAccCateg"
else
    echo "Wrong choice!"
fi