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Linux 从右侧提取两个/之间的字符串_Linux_Bash_Awk_Sed_Scripting - Fatal编程技术网

Linux 从右侧提取两个/之间的字符串

Linux 从右侧提取两个/之间的字符串,linux,bash,awk,sed,scripting,Linux,Bash,Awk,Sed,Scripting,从右侧提取两个/之间的字符串 命令准备: 输入:-[目录名称不是常量] 示例1:- /dir1/dir2/ /dir1/dir2/dir3/dir4/ nohup dsmc arch /dir1/dir2/ -subdir=yes > /tsm/backuplogs/dir2_`date +%d%m%y_%H_%M`.log & nohup dsmc arch /dir1/dir2/dir3/dir4/ -subdir=yes > /tsm/backuplogs/dir

从右侧提取两个/之间的字符串

命令准备:

输入:-[目录名称不是常量]

示例1:-

/dir1/dir2/
/dir1/dir2/dir3/dir4/
nohup dsmc arch /dir1/dir2/ -subdir=yes > /tsm/backuplogs/dir2_`date +%d%m%y_%H_%M`.log &
nohup dsmc arch /dir1/dir2/dir3/dir4/ -subdir=yes > /tsm/backuplogs/dir4_`date +%d%m%y_%H_%M`.log &
示例2:-

/dir1/dir2/
/dir1/dir2/dir3/dir4/
nohup dsmc arch /dir1/dir2/ -subdir=yes > /tsm/backuplogs/dir2_`date +%d%m%y_%H_%M`.log &
nohup dsmc arch /dir1/dir2/dir3/dir4/ -subdir=yes > /tsm/backuplogs/dir4_`date +%d%m%y_%H_%M`.log &
我希望输出如下

示例1输出:-

/dir1/dir2/
/dir1/dir2/dir3/dir4/
nohup dsmc arch /dir1/dir2/ -subdir=yes > /tsm/backuplogs/dir2_`date +%d%m%y_%H_%M`.log &
nohup dsmc arch /dir1/dir2/dir3/dir4/ -subdir=yes > /tsm/backuplogs/dir4_`date +%d%m%y_%H_%M`.log &
示例2输出:-

/dir1/dir2/
/dir1/dir2/dir3/dir4/
nohup dsmc arch /dir1/dir2/ -subdir=yes > /tsm/backuplogs/dir2_`date +%d%m%y_%H_%M`.log &
nohup dsmc arch /dir1/dir2/dir3/dir4/ -subdir=yes > /tsm/backuplogs/dir4_`date +%d%m%y_%H_%M`.log &

使用
basename
程序从路径中提取最后一个目录,如下所示:

上述行将输出:


尝试以下操作以提取子字符串:

basename /dir1/dir2/dir3/dir4/
输出:

dir4 输出

dir4 dir4
您应该避免使用旧的和不推荐使用的back tics,请使用以下括号:
\u\$(日期+%d%m%y\u%H\u%m\)。log