Loops 修改google应用程序脚本中的列表元素

我有以下两个列表：

list1 = [01-0160306, 01-0160302]
list2 = [[01-0160299, null, 3496.0, 1.0, null], [01-0160302, null, 18.0, 1.0, null], [01-0160306, null, 18.0, 1.0, null]]

如果列表1中有元素，则需要检索列表2中相应的数组，最后一个元素“null”必须替换为“Yes”。结果需要推回到列表2

if(list1.length > 0){
 for(i=0;i<list1.length;i++){
   for (j=0;j<list2.length;j++){
     if(list2[j][0] == i){ //if there is a match
      //Not sure how to modify and push it back to the list2
     }
  }
}}

因此，结果必须是

list2 = [[01-0160299, null, 3496.0, 1.0, null], [01-0160302, null, 18.0, 1.0, Yes], [01-0160306, null, 18.0, 1.0, Yes]]

我尝试在list1数组上循环，然后在list2上循环以获得它的第一个元素。但不确定如何检索这些行，请修改 并将其推回到列表2

if(list1.length > 0){
 for(i=0;i<list1.length;i++){
   for (j=0;j<list2.length;j++){
     if(list2[j][0] == i){ //if there is a match
      //Not sure how to modify and push it back to the list2
     }
  }
}}

if（list1.length>0）{
对于（i=0；i只需在所需数组元素中写入新值“Yes”

...
if(list2[j][0] == i){ //if there is a match
      list2[j][4] = 'Yes'   //Not sure how to modify and push it back to the list2
     }
...

只需在所需数组元素中写入新值'Yes'

...
if(list2[j][0] == i){ //if there is a match
      list2[j][4] = 'Yes'   //Not sure how to modify and push it back to the list2
     }
...