Makefile 如何在另一个带循环的Make recipe中运行Make recipe？

我有一个Makefile，如下所示：

run_experiment1:
    python some_file.py \
        --data_file /somewhere/here \
        --k ${k}

run_all_experiments:
    for k in 1 2 3 4 5 ; do \
        run_experiment1 k=$$k ; \
    done                        

当我运行

make run\u所有实验时

我得到：

for k in 1 2 3 4 5 ; do \
    run_experiment1 k= ; \
done
/bin/sh: 2: run_experiment1: not found
/bin/sh: 2: run_experiment1: not found
/bin/sh: 2: run_experiment1: not found
/bin/sh: 2: run_experiment1: not found
/bin/sh: 2: run_experiment1: not found
Makefile:84: recipe for target 'run_all_experiments' failed
make: *** [run_all_experiments] Error 127

---

我能立即注意到的是，

k

似乎没有像我预期的那样输入值，并且没有找到命令。我该如何着手解决这个问题？谢谢。

这确实是一个反模式。您希望构建您的

Makefile

，以便

make

自己负责

直接而明显的解决方法是，与错误消息提示一样，此处正确的命令是

make run\u experiment1

：

.PHONY: run_experiment1 run_all_experiments
run_experiment1:
    python some_file.py \
        --data_file /somewhere/here \
        --k $$k  # notice doubled dollar sign to escape it from make

run_all_experiments:
    for k in 1 2 3 4 5 ; do \
        $(MAKE) run_experiment1 k=$$k ; \
    done

然而，如上所述，我可能会将其重构为

.PHONY: run_experiment% run_all_experiments
run_experiment%:
    python some_file.py \
        --data_file /somewhere/here \
        --k $*

run_all_experiments: $(patsubst %,run_experiment%,1 2 3 4 5)

---

切向而言，应该声明与具有该名称的文件不对应的目标。

谢谢！只是好奇，你放在顶部的

.PHONY

是什么？更新了一个简短的解释和文档链接。