matlab中音频信号的峰值信噪比
我试图找出我的项目中音频文件的MSE和PSNR值。到目前为止,我编写的代码如下:matlab中音频信号的峰值信噪比,matlab,signal-processing,Matlab,Signal Processing,我试图找出我的项目中音频文件的MSE和PSNR值。到目前为止,我编写的代码如下: [y1,fs1, nbits1,opts1]=wavread('one.wav'); [y2,fs2, nbits2,opts2]=wavread('newOne.wav'); [c1x,c1y]=size(y1); [c2x,c2y]=size(y1); if c1x ~= c2x disp('dimeonsions do not agree'); else R=c1x; C=c1y; err =
[y1,fs1, nbits1,opts1]=wavread('one.wav');
[y2,fs2, nbits2,opts2]=wavread('newOne.wav');
[c1x,c1y]=size(y1);
[c2x,c2y]=size(y1);
if c1x ~= c2x
disp('dimeonsions do not agree');
else
R=c1x;
C=c1y;
err = (((y1-y2).^2)/(R*C));
MSE=sqrt(err);
MAXVAL=65535;
PSNR = 20*log10(MAXVAL/MSE);
disp(['mse=' num2str(MSE) ' PSNR=' num2str(PSNR)]);
end
但我得到的错误如下:
[y1,fs1, nbits1,opts1]=wavread('one.wav');
[y2,fs2, nbits2,opts2]=wavread('newOne.wav');
[c1x,c1y]=size(y1);
[c2x,c2y]=size(y1);
if c1x ~= c2x
disp('dimeonsions do not agree');
else
R=c1x;
C=c1y;
err = (((y1-y2).^2)/(R*C));
MSE=sqrt(err);
MAXVAL=65535;
PSNR = 20*log10(MAXVAL/MSE);
disp(['mse=' num2str(MSE) ' PSNR=' num2str(PSNR)]);
end
被连接矩阵的维数不一致。
我做错了什么???为了计算MSE-变化,您需要将误差平方相加:
err = (((y1-y2).^2)/(R*C));
致:
您需要对平方误差求和,以计算MSE-变化:
err = (((y1-y2).^2)/(R*C));
致:
您需要对平方误差求和,以计算MSE-变化:
err = (((y1-y2).^2)/(R*C));
致:
您需要对平方误差求和,以计算MSE-变化:
err = (((y1-y2).^2)/(R*C));
致: