Mongodb-包含元素但不包含另一个元素的数组

我正在尝试查询我的mongodb集合中的一个，如下所示：

> db.collection.find()
{name: "foo", things: [{stuff:"banana", value: 1}, {stuff:"apple", value: 2}, {stuff:"strawberry", value: 3}]}
{name: "bar", things: [{stuff:"banana", value: 4}, {stuff:"pear", value: 5}]}
...

db.transactions.find({
  "things": {
    $elemMatch: {
      "stuff": "banana", 
      $ne: {
        "stuff": "apple"
      }
    }
  }
)

我的目标是列出所有包含

things

字段的对象，该字段包含

stuff=banana

但不包含

stuff=apple

我试过这样的方法：

> db.collection.find()
{name: "foo", things: [{stuff:"banana", value: 1}, {stuff:"apple", value: 2}, {stuff:"strawberry", value: 3}]}
{name: "bar", things: [{stuff:"banana", value: 4}, {stuff:"pear", value: 5}]}
...

db.transactions.find({
  "things": {
    $elemMatch: {
      "stuff": "banana", 
      $ne: {
        "stuff": "apple"
      }
    }
  }
)

---

但它不起作用。有什么想法吗？

使用

$not

和

$and

操作符：

db.collection.find({

   $and:[
    {"things": {$elemMatch: {  "stuff": "banana"  }}},
    {"things": {$not: {$elemMatch: { "stuff": "apple"}}}}
  ]

});

---

下面的查询将获得所有文档的列表，这些文档的

things

字段包含

stuff=banana

但不包含

stuff=apple

的元素：

db.test.find（{“$and”：[{“things.stuff”：“banana”}，{“things.stuff”：{$ne:“apple”}]}）

使用$in和$nin包含和排除

db.transactions.find({
  "things.stuff": {
    $in: ["banana"], 
    $nin:["apple"]
  }
})