Ms access Access 2007：如何开始工作周和工作周并在结果上显示工作周日期

好的，我有一个查询，需要在输出上显示所有的周末日期，并在周日开始到周六结束的一周内对

callID

s进行计数

目前我正在插入startdate和enddate，但这不会在输出中累积周末

这意味着我希望在输出中看到的是：

• 2015年7月2日工作周15人（每位主管）

• 2015年2月14日周末25人

• 2015年2月21日周末9人
  选择不同的[Coach].[LastName]&“，”&[Coach].[FirstName]作为CoachName，Count（S.CallId）作为[Count]，tblLocations.LocationName，S.DateScored 从tblLocations内部联接（tblScores作为S内部联接TBlemEmployees作为Coach在S.CoachId=Coach.ID上）到tblLocations.ID=S.LocationId 按[Coach].[LastName]&“，”和[Coach].[FirstName]，tblLocations.LocationName，Coach.Source，S.Completed，S.DateScored分组

  ---

  有（（（tblLocations.LocationName）=“纳什维尔”或（tblLocations.LocationName）=“梭伦”或（tblLocations.LocationName）=“圣安东尼奥”或（tblLocations.LocationName）=“凤凰城”）和（（Coach.Source）=“主管”）和（（S.Completed）=是）和（（S.DateScored>=[开始日期]和（S.DateScored）您必须使用一些Access SQL函数：

  IIF（）

  、

  Weekday（）

  和

  DateAdd（）

  。基本上，您必须找到日期（1-7，对应于太阳周六），然后添加相应的值，以获取所有日期以返回周六日期：

  SELECT [Coach].[LastName] & ", " & [Coach].[FirstName] AS CoachName, 
       Count(S.CallId) AS [CountOfSupervisors], tblLocations.LocationName,  
       IIF(Weekday(S.DateScored) = 7, S.DateScored,
       IIF(Weekday(S.DateScored) = 6, DateAdd('d', 1, S.DateScored),
       IIF(Weekday(S.DateScored) = 5, DateAdd('d', 2, S.DateScored),
       IIF(Weekday(S.DateScored) = 4, DateAdd('d', 3, S.DateScored),
       IIF(Weekday(S.DateScored) = 3, DateAdd('d', 4, S.DateScored),
       IIF(Weekday(S.DateScored) = 2, DateAdd('d', 5, S.DateScored),
       IIF(Weekday(S.DateScored) = 1, DateAdd('d', 6, S.DateScored), Null))))))) As EndOfWeek
  
  FROM tblLocations INNER JOIN (tblScores AS S 
  INNER JOIN tblEmployees AS Coach ON S.CoachId = Coach.ID) ON tblLocations.ID = S.LocationId 
  WHERE (((tblLocations.LocationName IN ('Nashville','Solon','San Antonio','Phoenix') AND 
          ((Coach.Source)='Supervisor') AND ((S.Completed)=Yes) AND 
          ((S.DateScored)>=[Start Date] And (S.DateScored)<=[End Date]))
  
  GROUP BY [Coach].[LastName] & ", " & [Coach].[FirstName], tblLocations.LocationName, 
       Coach.Source, S.Completed, 
       IIF(Weekday(S.DateScored) = 7, S.DateScored,
       IIF(Weekday(S.DateScored) = 6, DateAdd('d', 1, S.DateScored),
       IIF(Weekday(S.DateScored) = 5, DateAdd('d', 2, S.DateScored),
       IIF(Weekday(S.DateScored) = 4, DateAdd('d', 3, S.DateScored),
       IIF(Weekday(S.DateScored) = 3, DateAdd('d', 4, S.DateScored),
       IIF(Weekday(S.DateScored) = 2, DateAdd('d', 5, S.DateScored),
       IIF(Weekday(S.DateScored) = 1, DateAdd('d', 6, S.DateScored), Null)))))));
  

  ---

  您会注意到我调整了您的一些代码。您可以将所有

  HAVING

  语句移动到

  WHERE

  子句中（

  HAVING

  在表示聚合时使用-Count、Sum、Avg、First、Last）。此外，您还可以将

  IN（）

  子句用于多个OR条件。希望这能奏效！
  考虑

  DateAdd（'d'，IIf（S.DateScored为Null，0，7-工作日（S.DateScored）），S.DateScored）作为EndOfWeek

  而不是那些嵌套的

  IIf

  表达式。另外

  SELECT DISTINCT

  在

  groupby

  查询中没有用处。谢谢大家，我将在完成必须生成的报告后立即回复：S

  SELECT [Coach].[LastName] & ", " & [Coach].[FirstName] AS CoachName, 
      Count(S.CallId) AS [CountOfSupervisors], tblLocations.LocationName,  
      DateAdd('d', IIf(S.DateScored Is Null, 0, 7 - Weekday(S.DateScored)), S.DateScored) As EndOfWeek
  
  FROM tblLocations INNER JOIN (tblScores AS S 
  INNER JOIN tblEmployees AS Coach ON S.CoachId = Coach.ID) ON tblLocations.ID = S.LocationId 
      WHERE (((tblLocations.LocationName IN ('Nashville','Solon','San Antonio','Phoenix') AND 
      ((Coach.Source)='Supervisor') AND ((S.Completed)=Yes) AND 
      ((S.DateScored)>=[Start Date] And (S.DateScored)<=[End Date]))
  
  GROUP BY [Coach].[LastName] & ", " & [Coach].[FirstName], tblLocations.LocationName, 
      Coach.Source, S.Completed, 
      DateAdd('d', IIf(S.DateScored Is Null, 0, 7 - Weekday(S.DateScored)), S.DateScored);